Question

我一直在尝试阅读以下网址的json响应

https://partner-int-api.groupon.com/deals.json?country_code=IN&tsToken=XXXXXXXXXXXXXXXXXX&CID=XXXXXXXXXXXXXXXXXX&nlp&utm_source=GPN&utm_medium=afl&utm_campaign=200321

或click here可以访问它。

我想得到

"price": {
   "amount": 49900,
   "formattedAmount": "Rs.499.00",
   "currencyCode": "INR"
}

如何阅读？

foreach($datas as $d)
{

    $list.= "<div class=frew>";         
    $list.= "<a href='".$d->dealUrl."'>".$d->announcementTitle."</a>";
    $list.= "<div>";
    $list.= "<div style='float:left;width:90%'><img src='".$d->mediumImageUrl."' />";
    $list.= "<div style='padding-left:2px;float:left'>".$d->title."
    <a class=css-button href='".$d->dealUrl."'>Click Here</a>   </br>
    <strong>Popularity: <a href='".$d->dealUrl."'> $d->soldQuantity </a></strong></br>
    </div></div>"; 
    $list.= "</div>";
    $list.= "</div>";

}

Answer 1

由于您知道返回json输出的URL，因此您需要主要两个PHP函数：

因此，您可以执行以下操作：

<?php
$q = "https://partner-int-api.groupon.com/deals.json?country_code=IN&tsToken=XXXXXXXXXXXXXXXXXX&CID=XXXXXXXXXXXXXXXXXX&nlp&utm_source=GPN&utm_medium=afl&utm_campaign=200321";
function readQuery($q){     
        $data = file_get_contents($q);
        return json_decode($data);
    }

echo "<pre>";
$res = readQuery($q);
$i = 0;
foreach ($res->deals as $deal){
    foreach ($deal->options as $option){
        $prices[$i]['amount'] = $option->price->amount;
        $prices[$i]['formattedAmount'] = $option->price->formattedAmount;
        $prices[$i]['currencyCode'] = $option->price->currencyCode;

    }
    $i++;
}
//var_dump($res->deals[1]->options[1]->price);
print_r($prices);

上述解决方案将返回一个数组，其中包含JSON资源中的所有价格。

Answer 2

假设$data已经包含您链接到的JSON文件中的内容：

$json = json_decode($data);
foreach ($json->deals as $deal) {
    $list.= "<div class=frew>";
    $list.= "<a href='".$deal->dealUrl."'>".$deal->announcementTitle."</a>";
    $list.= "<div>";
    $list.= "<div style='float:left;width:90%'><img src='".$deal->mediumImageUrl."' />";
    $list.= "<div style='padding-left:2px;float:left'>".$deal->title."
        <a class=css-button href='".$deal->dealUrl."'>Click Here</a>   </br>
        <strong>Popularity: <a href='".$deal->dealUrl."'> $d->soldQuantity </a></strong></br>
        </div></div>";
    $list.= "</div>";
    $list.= "</div>";
}

然后您可以回显$ list以查看该项目。

解析json的反应

2 个答案: