Question

我已经搜索了整个互联网来回答我的问题，但似乎没有人有同样的问题：我试图从子进程输出动态更新我的tkinter GUI，如果我＆＃ 39; m在eclipse中启动我的GUI。但如果我在文件资源管理器或视觉工作室中运行它，那么＆＃39; stdout.readline＆＃39;命令等待，直到子进程完成。只有这样才能将完整的输出打印到我的textarea ...我正在使用一个帖子，我尝试了两种方法：一种是在App.py＆＃39;中显示，另一种是在线程中＆＃39; read_update＆＃39;替代方法（而不是使用＆＃39; reader_thread＆＃39;以及＆＃39;更新＆＃39;方法）。

有趣的旁注：Test.py中的sys.argv命令不会返回我的字符串＆＃34; var_test＆＃34;。谁能告诉我为什么？

我的课程是：

GUI.py

import Tkinter as tk

from App import App

if __name__ == '__main__':
    root = tk.Tk()

    app = App(root)

    root.protocol("WM_DELETE_WINDOW", app.quit)
    root.mainloop()

App.py

#App.py
import Tkinter as tk
import tkFont as tkfont
import subprocess

from subprocess import Popen
from subprocess import PIPE
from itertools import islice
from threading import Thread
from ttk import Scrollbar
from Tkinter import *
from Queue import Queue, Empty

class App():
    def __init__(self, root):
        self.root = root
        self.root.title_font = tkfont.Font(family = "Helvetica", size = 18, weight = "bold", slant = "italic")

        Grid.columnconfigure(self.root, 5, weight = 1)

        button_ok = tk.Button(self.root, text = "OK", width = 10, command = lambda: self.on_okay())
        button_ok.grid(row = 7, column = 0, padx = (20,0), pady = 10, sticky = W)

        xscrollbar = Scrollbar(self.root, orient=HORIZONTAL)
        xscrollbar.grid(row=8, column=1, columnspan=4, sticky=E + W)

        yscrollbar = Scrollbar(self.root, orient=VERTICAL)
        yscrollbar.grid(row=8, column=5, sticky=N + S)

        self.textarea = Text(self.root, wrap=NONE, bd=0,
                             xscrollcommand=xscrollbar.set,
                             yscrollcommand=yscrollbar.set)
        self.textarea.grid(row=8, column=1, columnspan=4, rowspan=1,
                            padx=0, sticky=E + W + S + N)

    def on_okay(self):
        self.textarea.delete("1.0", END)

        exec_path = r"\Test.py" #insert location of Test.py

        self.process = subprocess.Popen([exec_path, 'var_test'], shell = True, stdout = subprocess.PIPE, stderr = subprocess.STDOUT)

        self.q = Queue(maxsize = 1024)
        t = Thread(target=self.reader_thread, args=[self.q])
        t.daemon = True
        t.start()

        self.update(self.q)

    def reader_thread(self, q):
        try:
            with self.process.stdout as pipe:
                for line in iter(pipe.readline, b''):
                    q.put(line)
        finally:
            q.put(None)

    def update(self, q):
        for line in self.iter_except(q.get_nowait, Empty):
            if line is None:
                #self.quit()
                return
            else:
                self.textarea.insert(INSERT, line)
                self.textarea.yview(END)
                break
        self.root.after(40, self.update, q)

    def iter_except(self, function, exception):
        try:
            while True:
                yield function()
        except exception:
            return

    def read_update(self):
        while True:
            line = self.process.stdout.readline()
            if line == "" and self.process.poll() != None:
                break
            elif line == "":
                pass
            else:
                self.textarea.insert(INSERT, line)
                self.textarea.yview(END)
                self.textarea.update_idletasks()    

    def quit(self):
        try:
            self.process.kill()
        except AttributeError:
            pass
        finally:
            self.root.destroy()

Test.py

import sys

from time import sleep

var = sys.argv
print var

for i in range(1, 10):
    print i

print "finished printing numbers"

sleep(10)

print "finished"

感谢您的帮助！我非常绝望，因为我一直试图解决这个问题好几个小时......

Answer 1

打印后使用sys.stdout.flush（）

Tkinter：实时从子进程输出更新GUI

1 个答案: