Question

除了$ sqlImg（应该将上传的图像插入表格）之外的所有内容都正常工作。有人可以向我解释为什么它不起作用？或者，如果有另一种方式可行，我很乐意听到它。下面的文件是我的upload.inc.php。我打算在将一个名为home.php的文件插入我的桌面后回显该图像。

<?php

if (!isset($_SESSION)) {
session_start();}

include_once 'includes/dbh.inc.php';
$id = $_SESSION['key'];

if (isset($_POST['submitFile'])) {
$file = $_FILES['file'];

$fileName = $file['name'];
$fileTmpName = $file['tmp_name'];
$fileSize = $file['size'];
$fileError = $file['error'];
$fileType = $file['type'];

$fileExt = explode('.', $fileName);
$fileActualExt = strtolower(end($fileExt));


$allowed = array('jpg', 'jpeg', 'png');

if (in_array($fileActualExt, $allowed)) {
    if ($fileError == 0) {
        if ($fileSize < 1000000) {
            $fileNameNew = "profile".$id.".".$fileActualExt;
            $fileDestination = 'uploads/'.$fileNameNew;
            move_uploaded_file($fileTmpName, $fileDestination);

            $sql = "UPDATE profileimg SET status=0 WHERE userid='$id';";
            mysqli_query($conn, $sql);

            $sqlImg = "INSERT INTO profileimg (image) WHERE userid='$id' VALUES ($fileNameNew);";
            mysqli_query($conn, $sqlImg);

            header("Location: home.php?upload=success");
        }
        else { echo "Sorry, your file size is too big.";}
    }
    else { echo "Oops, an error occurred!";}
}
else { echo "Please upload png and jpg files only.";}
}

Answer 1

您正在对新图片进行INSERT。我认为你需要UPDATE。

更改：

$sql = "UPDATE profileimg SET status=0 WHERE userid='$id';";

要

$sql = "UPDATE profileimg SET status=0, image = '$fileNameNew' WHERE userid='$id';";

并删除：

$sqlImg = "INSERT INTO profileimg (image) WHERE userid='$id' VALUES ($fileNameNew);"; mysqli_query($conn, $sqlImg);

你正在以错误的方式进行session_start（）。它应该一直被调用。

更改：

if (!isset($_SESSION)) { session_start();}

要

if (session_status() == PHP_SESSION_NONE) { session_start(); }

Answer 2

$sqlImg = "INSERT INTO profileimg (image) WHERE userid='$id' VALUES ($fileNameNew);";
        mysqli_query($conn, $sqlImg);

应该是

$sqlImg = "INSERT INTO profileimg (image) WHERE userid=".$id." VALUES (".$fileNameNew.")";
        mysqli_query($conn, $sqlImg);

用户上传的图片未插入表

2 个答案: