数据未插入表中

时间:2012-09-18 23:20:01

标签: php mysql database mysqli

我使用下面的代码上传文件并使用mysqli将数据插入“Image”表:

<?php
/* check connection */
if (mysqli_connect_errno()) {
    printf("Connect failed: %s\n", mysqli_connect_error());
    die();
}

$result = 0;

//UPLOAD IMAGE FILE

move_uploaded_file($_FILES["fileImage"]["tmp_name"], "ImageFiles/" . $_FILES["fileImage"]["name"]);

$result = 1;

//INSERT INTO IMAGE DATABASE TABLE

$imagesql = "INSERT INTO Image (ImageFile) VALUES (?)";

if (!$insert = $mysqli->prepare($imagesql)) {
    // Handle errors with prepare operation here
}

//Dont pass data directly to bind_param store it in a variable
$insert->bind_param("s", $img);

//Assign the variable
$img = 'ImageFiles/' . $_FILES['fileImage']['name'];

$insert->execute();

$insertimagequestion->execute();

//IF ANY ERROR WHILE INSERTING DATA INTO EITHER OF THE TABLES
if ($insert->errno) {
  // Handle query error here
}

$insert->close();


$lastID = $mysqli->insert_id;

 $imagequestionsql = "INSERT INTO Image_Question (ImageId, SessionId, QuestionId) 
    VALUES (?, ?, ?)";


    if (!$insertimagequestion = $mysqli->prepare($imagequestionsql)) {
      // Handle errors with prepare operation here
       echo "Prepare statement err";
    }

$sessid =  $_SESSION['id'] . ($_SESSION['initial_count'] > 1 ? $_SESSION['sessionCount'] : '');

$insertimagequestion->bind_param("isi",$lastID, $sessid, $_POST['numQuestion'][$i]);

        $insertimagequestion->execute();

                if ($insertimagequestion->errno) {
          // Handle query error here
        }

        $insertimagequestion->close();

}
?>

例如,如果我将2个图像“cat.png”和“dog.png”插入“图像”数据库表中,它将像这样插入:

  ImageId         ImageFile

    220             cat.png
    221             dog.png

(ImageId is an auto increment)

无论如何,我想要做的是,当上传文件时,不仅将数据插入到上面的表中,而且我还希望能够检索上面插入的ImageId并将其放在“Image_Question”中“下面的表格就是这样:

ImageId         SessionId      QuestionId

    220            AAA             1 
    221            AAB             4

但它没有在Image_Question表中插入任何内容。如何上传图像,它不仅可以将数据插入“图像”表,还可以将数据插入“Image_Question”表中?

1 个答案:

答案 0 :(得分:1)

原谅我,如果我离开了,但不是php顺序执行,换句话说, 不应该这样:$insertimagequestion->execute(); 追求这个:if (!$insertimagequestion = $mysqli->prepare($imagequestionsql)) ? 也许$insertimagequestion->execute();的第一次出现可能会消除插入ID。我会把东西打印出去确保你获得了insert_id。