如何为column / row_colors添加更多间距?在添加3行或更多行后,它看起来非常密集
#modified example data is from this question: https://stackoverflow.com/questions/48173798/additional-row-colors-in-seaborn-cluster-map
matrix = pd.DataFrame(np.random.random_integers(0,1, size=(50,4)))
labels = np.random.random_integers(0,5, size=50)
lut = dict(zip(set(labels), sns.hls_palette(len(set(labels)), l=0.5, s=0.8)))
row_colors = pd.DataFrame(labels)[0].map(lut)
#Create additional row_colors here
labels2 = np.random.random_integers(0,1, size=50)
lut2 = dict(zip(set(labels2), sns.hls_palette(len(set(labels2)), l=0.5, s=0.8)))
row_colors2 = pd.DataFrame(labels2)[0].map(lut2)
# add more rows
row_colors = pd.concat([row_colors,row_colors,row_colors2,row_colors2,row_colors2],axis=1)
g=sns.clustermap(matrix, col_cluster=False, linewidths=0.1, cmap='coolwarm', row_colors=row_colors)
plt.show()
答案 0 :(得分:0)
您可以调整for(id in 1:nrow(df2)){
Xfind<-df$Role_Primary[df$uniqueID %in% df2$uniqueID[id]]
if (any(Xfind=="X")){df2$Role_Primary[id]<-"X"}
Xfind2<-df$Role_Signatory[df$uniqueID %in% df2$uniqueID[id]]
if (any(Xfind2=="X")){df2$Role_Signatory[id]<-"X"}
Xfind3<-df$Role_Comms[df$uniqueID %in% df2$uniqueID[id]]
if (any(Xfind3=="X")){df2$Role_Comms[id]<-"X"}
}
参数。
df2
会给你更多的间距。