我有一个包含两列用户和详细信息的表。我只需要记录用户只有过期和推荐的详细信息，而不是过期，推荐，丢失和处理的用户。
**Users Details**
1560 Overdue
1560 Overdue
1560 Referral
1470 Overdue
1470 Referral
1470 Lost
1470 Processing
1480 Referral
1480 Lost
1480 Processing
1356 Referral
1356 Overdue
1289 Referral
Output has to be:
1560
1356
1289
答案 0 :(得分：4)
一种方法是按` form.setScript('customscript_toloader')
form.addButton('custpagetestbutton', 'TEST button', 'createTO();');`
对数据进行分组，然后只采用那些需要function createTO() //(request, response)
{
alert("This function was called");
//variable set up
nlapiLogExecution('DEBUG', 'script', 'runs 1');
var POID ;
var POType ;
var PORecord;
var lines;
nlapiLogExecution('DEBUG', 'script', 'runs 2');
var arrayName = new Array();
var arrayQty = new Array();
PORecord = nlapiGetNewRecord();
lines = PORecord.getLineItemCount('item');
POID = nlapiGetRecordId();
POTYPE = nlapiGetRecordType();
// get name and quantity
for ( var i = 1; i < lines + 1 ; i++ )
{
arrayName[i] = PORecord.getLineItemValue('item', 'item', i );
arrayQty[i] = PORecord.getLineItemValue('item', 'quantity' , i);
}
nlapiLogExecution('DEBUG', 'script', 'runs 3');
//creates to and changes focus
var TOrecord = nlapiCreateRecord ('transferorder');
var TOrecordID = TOrecord.getId();
TOrecord.setFieldValue('customform',128);
//subsidiaries CC bedford id is 2
TOrecord.setFieldValue('subsidiary',2);
//testing for location and transfer location, 144 & 145
TOrecord.setFieldValue('location',144);
TOrecord.setFieldValue('transferlocation',145);
TOrecord.setFieldValue('memo', 'PO: ' + POID );
TOrecord.setFieldValue('employee',nlapiGetContext().getUser());
//TOrecord.setFieldValue('department',"C-C");
//set name and quantity
for ( var j = 1; j < lines +1 ; j++ )
{
arrayName[j] = parseInt(arrayName[j]);
TOrecord.setLineItemValue("item", "item", j , arrayName[j] );
TOrecord.setLineItemValue("item", "quantity", j , parseInt(arrayQty[j])); //added parse int, should work
}
// set the item and location values on the currently selected line
nlapiSetCurrentLineItemValue('item', 'location', 6);
// commit the line to the database
//nlapiCommitLineItem('item');
var TOResult = nlapiSubmitRecord(TOrecord, true, true);
var TOTranID= nlapiLookupField('transferorder', TOResult, 'tranid');
var poURL = nlapiResolveURL('RECORD', 'transferorder', TOResult);
nlapiSetRedirectURL('RECORD','transferorder', TOResult);
return;
}
但不包含其他人的数据
users如果您 希望用户 details或select users
from your_table
group by users
having sum(case when details = 'Referral' then 1 else 0 end) > 0
and sum(case when details = 'Overdue' then 1 else 0 end) > 0
and sum(case when details not in ('Referral', 'Overdue') then 1 else 0 end) = 0
，那么
Referral答案 1 :(得分：0)
SELECT DISTINCT
UD1.user_id
FROM
User_Details UD1
INNER JOIN User_Details UD2 ON
UD2.user_id = UD1.user_id AND
UD2.description = 'Referral'
WHERE
UD1.description = 'Overdue' AND
NOT EXISTS (
SELECT *
FROM User_Details UD3
WHERE
UD3.user_id = UD1.user_id AND
UD3.description NOT IN ('Overdue', 'Referral')
)
答案 2 :(得分：0)
你可以这样做。查询具有单行的中间映射表，指示每个用户正在使用哪些详细信息。 只需按表格名称更改[YOUR_TABLE]：
SELECT MAPPING.USERS
FROM (SELECT USERS
,CASE WHEN SUM(CASE WHEN DETAILS = 'Overdue' THEN 1 ELSE 0 END) >= 1 THEN 1 ELSE 0 END AS HAS_OVERDUE
,CASE WHEN SUM(CASE WHEN DETAILS = 'Lost' THEN 1 ELSE 0 END) >= 1 THEN 1 ELSE 0 END AS HAS_LOST
,CASE WHEN SUM(CASE WHEN DETAILS = 'processing' THEN 1 ELSE 0 END) >= 1 THEN 1 ELSE 0 END AS HAS_PROCESSING
,CASE WHEN SUM(CASE WHEN DETAILS = 'referral' THEN 1 ELSE 0 END) >= 1 THEN 1 ELSE 0 END AS HAS_REFERRAL
FROM [YOUR_TABLE]
GROUP BY USERS) AS MAPPING
WHERE (MAPPING.HAS_OVERDUE = 1 OR MAPPING.HAS_REFERRAL = 1)
AND (MAPPING.HAS_LOST + MAPPING.HAS_PROCESSING) < 2
答案 3 :(得分：0)
我只会使用not exists：
select distinct t.users
from table t
where not exists (select 1
from table
where users = t.users and
details in ('lost', 'Processing')
);