Question

我有一个科目和一个科目表，每个科目都与科目表相关联。我正在尝试选择所有科目，包括部门名称。代码下面的工作完美，但只显示两个记录。任何帮助将不胜感激

//Select statement
$selects=$connection->query("SELECT
subjects.id
, subjects.name
, subjects.related_to
, subjects.related_to_sem
, departments.dept
FROM subjects
INNER JOIN departments
ON subjects.related_to = departments.dep_id");

<table class="table table-striped table-bordered bootstrap-datatable datatable">
<thead>
<tr>
<th>Sub Id</th>
<th>Subject Name</th>
<th>Related to Department</th>
<th>Related to Semester</th>
<th>Actions</th>
</tr>
</thead>   
<tbody>
<?php
while($result=$select->fetch_assoc()) { 
?>
<tr>
  <td><?php echo $result['id']; ?></td>
  <td class="center"><?php echo $result['name']; ?></td>
  <td class="center"><?php echo $result['dept']; ?></td>
 <td class="center"><?php echo $result['related_to_sem']; ?></td>
 <td class="center">
 <a class="btn btn-info" href="#">
<i class="icon-edit icon-white"></i>  
Edit                                            
</a>
<a class="btn btn-danger" href="#">
<i class="icon-trash icon-white"></i> 
Delete
</a>
</td>
</tr>
<?php } ?>
</tbody>
</table>

Answer 1

select 

subjects.id,subjects.name,
subjects.related_to,
subjects.related_to_sem,
departments.dept 

from 

subjects

LEFT OUTER JOIN departments ON subjects.id=departments.dep_id

Answer 2

请尝试以下方法。我想你可能在连接条件中使用了错误的字段：

SELECT
      subjects.id
    , subjects.name
    , subjects.related_to
    , subjects.related_to_sem
    , departments.dept
FROM subjects
      INNER JOIN departments
                  /* ON subjects.id = departments.dep_id */
                  ON subjects.dep_id = departments.id

部门科目表中的“外键”更有可能成为subjects.dep_id

Inner Join只从mysql中选择两条记录

2 个答案: