Question

我正在写博客 - 它有顶部栏菜单，其中包含Categories个对象。问题是此博客中的每个视图都必须返回context Categories.objects.all()。有没有更好的方法来解决这个问题（将相同的查询集添加到每个视图的上下文）？我的代码：

models.py

class Category(models.Model):
    name = models.CharField(max_length=60)
    slug = models.SlugField(unique=True, blank=True, null=True)

base.html文件

<!DOCTYPE html>
<html lang="en">
<head>
    <meta charset="UTF-8">
    <title>Blog</title>  
</head>
<body>
    {% block menu %}
        <div id="menu">
        {% for item in categories %}
            <a href="{% url 'category_detail' item.slug %}">
                <div class="category">{{ item.name }}</div>
            </a>
        {% endfor %}
        </div>
    {% endblock %}

    {% block content %}
    <!-- I want extend only that block in every view -->

    {% endblock %}
</body>
</html>

Answer 1

您可以通过上下文处理器发送它。只需在settings.py旁边的根项目中添加一个文件，将其命名为context_processor.py，然后在内部编写function，其中request为参数，必须返回字典

from your_app.models import Category def global_context(request): cateogries = Category.objects.all() context = {'categories':categories,} return context

然后你从settings.py
调用它
TEMPLATES = [ { 'BACKEND': 'django.template.backends.django.DjangoTemplates', 'APP_DIRS': True, # codes, 'OPTIONS':{ 'context_processors':[ 'django.contrib.auth.context_processors.auth', 'django.template.context_processors.debug', 'django.template.context_processors.i18n', 'django.template.context_processors.media', 'django.template.context_processors.static', 'django.template.context_processors.tz', 'django.contrib.messages.context_processors.messages', 'django.contrib.messages.context_processors.messages', # Insert your TEMPLATE_CONTEXT_PROCESSORS here #'project_name.file_name.function_name', 'project_name.context_processors.global_context', ], } }, ]

Answer 2

通过继承%-7

创建一个mixin类

ContextMixin

现在，在您需要类别的每个视图中都会继承from django.views.generic.base import ContextMixin class CategoryMixin(ContextMixin): """ A mixin class that adds categories to all the views that use it. """ def get_context_data(self, **kwargs): ctx = super(CategoryMixin, self).get_context_data(**kwargs) ctx['categories'] = Categories.objects.all() return ctx

CategoryMixin

Django - 始终呈现的上下文

2 个答案: