Question

根据这个JSON Insert into a MySQL table or update if exists，我得到了回答mysql来插入/更新下面的json。

"google", 
"20180510", 
"{
   "gmail_page_viewed" : 12000300, 
   "search_page_viewed" : 9898884726423
 }"

进入SCHEMA

CREATE TABLE TAG_COUNTER (
    account       varchar(36) NOT NULL,
    time_id       INT NOT NULL,
    counters      JSON,
    PRIMARY KEY   (account, time_id)
)

如下所示

INSERT INTO `TAG_COUNTER`
  (`account`, `time_id`, `counters`)
VALUES
  ('google', '20180510', '{"gmail_page_viewed": 1, "search_page_viewed": 1}'),
  ('google', '20180510', '{"gmail_page_viewed": 1, "search_page_viewed": 1}'),
  ('google', '20180511', '{"gmail_page_viewed": 1, "search_page_viewed": 1}'),
  ('google', '20180511', '{"gmail_page_viewed": 1, "search_page_viewed": 1}'),
  ('google', '20180512', '{"gmail_page_viewed": 1, "search_page_viewed": 1}')
ON DUPLICATE KEY UPDATE `counters` =
  JSON_SET(`counters`,
           '$."gmail_page_viewed"',
           IFNULL(`counters` ->> '$."gmail_page_viewed"', 0) + 1,
           '$."search_page_viewed"',
           IFNULL(`counters` ->> '$."search_page_viewed"', 0) + 1
  );

然而，使用group by很难从中检索数据，因为json键是动态的而不是静态的。

因此，如果我将json更改为具有以下格式的静态密钥（例如page_name，page_visits），则可以轻松进行检索（groupby / orderby）。

"google", 
"20180510", 
'{
   "gmail_page_viewed" : {"page_name" : "gmail_page_viewed", "page_visits" : 12000300}, 
   "search_page_viewed" : {"page_name" : "search_page_viewed", "page_visits" : 12000300}
 }"

但我无法弄清楚如何准备INSERT ON DUPLICATE KEY UPDATE查询。我已经尝试了6个多小时，但没有运气，数据插入不正确，或者没有正确更新访问次数。有时引用会被添加到内容中。

有人可以帮我吗？

MySql Inner JSON如果存在则插入或更新

0 个答案: