Question

import java.util.Scanner;

public class Solution {
//java program for accepting an integer, an double and a set of string from the user.

    public static void main(String[] args) {
        Scanner scan = new Scanner(System.in);
        int i = scan.nextInt();
        double d= scan.nextDouble();
        String s= scan.nextLine();

        scan.next();
        scan.nextLine();//clearing input buffer.
        //printing the inputs taken from the user.
        System.out.println("String: " + s);
        System.out.println("Double: " + d);
        System.out.println("Int: " + i);
    }
}

Answer 1

按enter键时，\n特殊字符将保留在缓冲区中。因此，在double d= scan.nextDouble();之后，缓冲区将保留\n并将其存储在行String s= scan.nextLine();中的字符串s中。要摆脱它，只需修改你的代码：

Scanner scan = new Scanner(System.in);
int i = scan.nextInt();
double d= scan.nextDouble();

// this will clear the '\n'
scan.nextLine();

String s= scan.nextLine();

//printing the inputs taken from the user.
System.out.println("String: " + s);
System.out.println("Double: " + d);
System.out.println("Int: " + i);

另一种处理方法是始终使用nextLine();进行扫描并按照您希望的方式进行解析。这样做可以更容易地检查用户输入的数据是否有效。

为什么此清除输入缓冲区未运行？

1 个答案: