在这个程序中,当我输入8个字符时,它会搞砸整个程序,我认为当你输入大于或等于SIZE字符时清除输入缓冲区有什么关系,我怎么做到这一点它清除用户可能输入的任何字符溢出? 谢谢你的帮助!
#include <stdio.h>
#define SIZE 8
int CharIsAt(char *pStr,char ch,int loc[],int mLoc);
int main(void){
char array[SIZE],search;
int found[SIZE],i,charsFound;
printf("Enter a line of text(empty line to quit): ");
while (fgets(array,SIZE, stdin)!=NULL && array[0]!='\n'){ //Loop until nothing is entered
printf("Enter a character to search: ");
search=getchar();
charsFound=CharIsAt(array,search,found,SIZE);
printf("Entered text: ");
fputs(array,stdout); //Prints text inputted
printf("Character being searched for: %c\n",search); //Prints character being searched for
printf("Character found at %d location(s).\n",charsFound); //Prints # of found characters
//Prints the location of the characters found relative to start of line
for (i=0;i<charsFound;i++)
printf("'%c' was found at %d\n",search,found[i]);
if (fgets(array,SIZE,stdin)==NULL) //Makes loop re-prompt
break;
printf("\nEnter a line of text(empty line to quit): ");
}
return 0;
}
int CharIsAt(char *pStr,char ch,int loc[],int mLoc){
//Searches for ch in *pStr by incrementing a pointer to access
//and compare each character in *pStr to ch.
int i,x;
for (i=0,x=0;i<mLoc;i++){
if (*(pStr+i)==ch){
//Stores index of ch's location to loc
loc[x]=i;
x++; //Increment for each time ch was counted in pStr
}
}
//Returns the number of times ch was found
return x;
}