Question

SELECT  YEAR, period, round((1- sum(rej_qty) / sum(recd_qty))*100, 0)   
 FROM   TAB_A
 WHERE  sid = '200'
 AND    sdid IN ('4750')
 AND
(
       (
          YEAR ='2011'
       AND    period IN('01_JAN')
       )
OR
       (
          YEAR = '2010'
       AND    period IN('02_FEB','03_MAR','04_APR','05_MAY','06_JUN','07_JUL','08_AUG','09_SEP','10_OCT','11_NOV','12_DEC')
       )
)
group by year, period

对于某个特定月份，recd_qty为ZERO，因为我得到DIVIDE BY ZERO错误。

有没有办法避免DIVIDE BY ZERO错误？

我有什么方法可以忽略那个特定的月份？

Answer 1

您是否尝试过使用NULLIF()？

 SELECT
 ( 100 / NULLIF( 0, 0 ) ) AS value
 ;

Oracle Doc
http://www.oracle-base.com/articles/9i/ANSIISOSQLSupport.php#NULLIFFunction

另一个例子
http://www.bennadel.com/blog/984-Using-NULLIF-To-Prevent-Divide-By-Zero-Errors-In-SQL.htm

Answer 2

如果要忽略此类记录，可以使用子查询

SELECT  YEAR, period, round((1- rej_sum / recd_sum)*100, 0) FROM
(
  SELECT YEAR, sum(rej_qty) rej_sum, sum(recd_qty) recd_sum
  FROM   TAB_A
  WHERE  sid = '200'
  AND    sdid IN ('4750')
  AND
  (
       (
          YEAR ='2011'
       AND    period IN('01_JAN')
       )
  OR
  (
      YEAR = '2010'
       AND    period IN ('02_FEB','03_MAR','04_APR','05_MAY','06_JUN','07_JUL','08_AUG','09_SEP','10_OCT','11_NOV','12_DEC')
       )
  )
  group by year, period
)
WHERE recd_sum <> 0;

如果你想保留它们并通过零问题处理除法，你可以使用解码或案例

SELECT  YEAR, period, DECODE(recd_qty, 0, NULL, round((1- sum(rej_qty) / sum(recd_qty))*100, 0))

Answer 3

round(ISNULL(
((1- sum(rej_qty)) / NULLIF( (sum(recd_qty))*100), 0 )),
0
),0)

如果使用NULLIF替换除法以在除以零时设置NULL，则使用ISNULL将NULL替换为0 - 或者实际上是您想要的值。

Answer 4

case sum（recd_qty）<> 0 THEN round（（1- sum（rej_qty）/ sum（recd_qty））* 100，0）ELSE 0 END

如何避免SQL查询中的DIVIDE BY ZERO错误

4 个答案: