Question

您好请参考我在模型中的以下代码

public function common_report($where) {
    $this->db->select('*');
    $this->db->from('collect_data_form_history_db as ch');
    $this->db->join('board_artwork_history_db as bh','bh.shop_id = ch.shop_id');
    $this->db->where('bh.shop_id', $where);
    // $this->db->where('bh.shop_id',$where);
    $query = $this->db->get();
    return $query->result_array();
}

我想要的是来自table_data_form_history_db和board_artwork_history_db的所有数据。我得到的数据但格式错误。在表格＆＃39; collect_data_form_history_db＆＃39;我有11个条目，在board_artwork_history_db我有18个条目。所以我得到的数据应该是29行，但我获得198行意味着11 * 18。请告诉我解决方案

Answer 1

你需要使用左连接。试试这种方式

$this->db->join('board_artwork_history_db as bh','bh.shop_id = ch.shop_id', 'left');

Answer 2

 $this->db->select('t1.*, t2.*')
          ->from('collect_data_form_history_db t1, board_artwork_history_db t2')
          ->where('t1.shop_id = t2.shop_id')
          ->where('t2.shop_id', $where);

$query = $this->db->get();

Answer 3

尝试完全外连接

public function common_report($where) {
    $this->db->select('*');
    $this->db->from('collect_data_form_history_db as ch');
    $this->db->join('board_artwork_history_db as bh','bh.shop_id = ch.shop_id', 'full outer');
    $this->db->where('bh.shop_id', $where);
    // $this->db->where('bh.shop_id',$where);
    $query = $this->db->get();
    return $query->result_array();
}

如何从codeigniter中具有相同列名的两个不同表中选择数据

3 个答案: