我需要从表中选择具有以下组合的值
SELECT Details FROM Avenger WHERE Id = '1' AND KEY LIKE '11AX';
SELECT Details FROM Avenger WHERE Id = '1' AND KEY LIKE '34XA';
SELECT Details FROM Avenger WHERE Id = '1' and KEY = '11AZ';
SELECT Details FROM Avenger WHERE Id = '1' AND KEY LIKE '11ZA';
在单个查询中,我知道我可以使用
SELECT * FROM Avenger WHERE ID='1';
但是我需要使用所有选定的值,并在单个查询中将其分配给四个变量。
我可以使用的任何想法或解决方案吗?
Id Key Details
1 11AX Mark
1 34XA Bruce
1 11AZ Mr. Green
1 11ZA Hulk
2 11AX Robert jr.
2 34XA Toney
2 11AZ Iron Man
2 11ZA Arrogant
3 11AX Thor
3 34XA Asgard
3 11AZ God
3 11ZA Hamer
答案 0 :(得分:1)
我们可以尝试在此处交替使用REGEXP_LIKE
:
SELECT *
FROM yourTable
WHERE Id = '1' AND REGEXP_LIKE("KEY", '11AX|34XA|11AZ|11ZA')
实际上,我不确定您是否打算在原始查询中使用LIKE
。您可能真的只想这样做:
SELECT *
FROM yourTable
WHERE Id = '1' "KEY" IN ('11AX', '34XA', '11AZ', '11ZA')
答案 1 :(得分:1)
我认为您想要一个case
表达式:
select details,
(case when key like '11AX' then 1
when key like '34XA' then 2
when key like '11AZ' then 3
when key like '11ZA' then 4
end) as flag
from avenger a
where id = 1;
如果只想使用一个表达式选择值,请以in
开头:
where id = 1 and key in ('11AX', '34XA', '11AZ', '11ZA')
如果要将值作为单个字符串传递,则regexp_like()
可以起作用:
where id = 1 and regexp_like(key, '^11AX|34XA|11AZ|11ZA$')
两个注意事项:
key
。regexp_like()
通常不使用索引,因此对于性能而言,=
和in
是更好的选择。也许你打算:
select max(case when key like '11AX' then details end) as deails_11ax,
max(case when key like '34XA' then details end) as details_34XA,
max(case when key like '11AZ' then details end) as details_11AZ,
max(case when key like '11ZA' then details end) as details_11AZ
from avenger a
where id = 1;
这将返回一行包含四列。
答案 2 :(得分:1)
我认为我了解您想要这个:
select
(SELECT Details FROM Avenger WHERE Id = '1' AND KEY LIKE '11AX') as var1,
(SELECT Details FROM Avenger WHERE Id = '1' AND KEY LIKE '34XA') as var2,
(SELECT Details FROM Avenger WHERE Id = '1' and KEY = '11AZ') as var3,
(SELECT Details FROM Avenger WHERE Id = '1' AND KEY LIKE '11ZA') as var4
from dual
还有一个pivot选项