我无法在文档中找到如何浏览"通过XmlNodeList中已有的节点。
鉴于此XML:
<?xml version="1.0" encoding="utf-8"?>
<!DOCTYPE tmx SYSTEM "tmx14.dtd">
<tmx version="1.4">
<tu changedate="20180509T145123Z" creationdate="20180509T145123Z" >
<prop type="aligned">no</prop>
<prop type="x-context">320920</prop>
<tuv xml:lang="en-gb">
<seg>Hello1</seg>
</tuv>
<tuv xml:lang="es">
<seg>Hola1</seg>
</tuv>
</tu>
<tu changedate="20180509T145216Z" creationdate="20180509T145216Z" >
<prop type="aligned">no</prop>
<prop type="x-context">325152</prop>
<tuv xml:lang="en-gb">
<seg>Hello2</seg>
</tuv>
<tuv xml:lang="es">
<seg>Hola2</seg>
</tuv>
</tu>
</tmx>
我正在尝试遍历每个/ tu中的不同节点以将其加载到数据库。应该很简单,但我正在努力学习语法。
到目前为止,我有这个:
Dim tmxfile As String = "d:\Documents\Desktop\myxml.xml"
Dim xmldoc As New XmlDocument
xmldoc.Load(tmxfile)
Dim nodes As XmlNodeList = xmldoc.DocumentElement.SelectNodes("//tu")
For node = 0 To nodes.Count - 1
Dim x = nodes.Item(node).SelectNodes("/seg")
MsgBox(x.ToString)
Next
End Sub
我想要实现的是在// tu中显示每个/ seg。代码的第一部分很好,好像我用innerxml或innertext循环遍历节点我看到了XML的实际元素,但我很难在这些节点上获取指定的元素。
任何指导?
提前致谢!
答案 0 :(得分:0)
如果您使用XDocument代替XmlDocument,则可以使用独特的VB功能 - XML Literals:
Sub Main()
Dim xml =
<?xml version="1.0" encoding="utf-8"?>
<tmx version="1.4">
<tu changedate="20180509T145123Z" creationdate="20180509T145123Z">
<prop type="aligned">no</prop>
<prop type="x-context">320920</prop>
<tuv xml:lang="en-gb">
<seg>Hello1</seg>
</tuv>
<tuv xml:lang="es">
<seg>Hola1</seg>
</tuv>
</tu>
<tu changedate="20180509T145216Z" creationdate="20180509T145216Z">
<prop type="aligned">no</prop>
<prop type="x-context">325152</prop>
<tuv xml:lang="en-gb">
<seg>Hello2</seg>
</tuv>
<tuv xml:lang="es">
<seg>Hola2</seg>
</tuv>
</tu>
</tmx>
xml.AddFirst(New XDocumentType("tmx", "SYSTEM", "tmx14.dtd", ""))
' All <tu> elements
Dim tus = xml.<tmx>.<tu>
For Each tu In tus
Dim seg = tu.<tuv>.<seg>
Console.WriteLine(seg.Value)
Next
Console.ReadKey(True)
End Sub