Question

我有这个XML文件

<?xml version="1.0" encoding="utf-8"?>
<message>
  <success/>
  <bookings>
    <booking>
      <rooms>
        <room roomCode ="101" uniqueId="abc">
          <stays>
            <stay usedfrom="9:30" usedto="10:30" quantity="1" Price="62.5" rateCode="1"/>
          </stays>
          <extras>
            <extra from="9:30" to="10:30" unitPrice="5.5" extraCode="coffee" quantity="1" inclusive="0"/>
          </extras>
          <guests>
            <guest firstName="John" lastName="Doe" title="MR" ageRange="0"/>
          </guests>
        </room>
        <room roomCode ="Brd" uniqueId="xyz">
          <stays>
            <stay usedfrom="13:30" usedto="15:30" quantity="1" unitPrice="60.0000" rateCode="RACK"/>
          </stays>
          <guests>
            <guest firstName="Jean" lastName="Doe" title="MRS" ageRange="0"/>
          </guests>
        </room>
      </rooms>
    </booking>
  </bookings>
</message>

我正在尝试获取节点，并通过下面的所有（NO s）节点（以及子节点）进行循环。我已经完成了这个，但它列出了每个循环的所有属性。

foreach (XmlNode Roomnode in RoomS)
{
    XmlNodeList Room = doc.GetElementsByTagName("room");
    var RoomCount = Room.Count;
    Console.WriteLine("This Booking contains " + RoomCount + " room(s)");

    foreach (XmlNode rmxn in Room)
    {
        RoomCode = rmxn.Attributes["roomCode"].Value;
        UniqueId = rmxn.Attributes["uniqueId"].Value;
        Console.WriteLine("         Room Type: " + RoomCode);
        Console.WriteLine("         Room id: " + UniqueId);

        XmlNodeList Stay = doc.GetElementsByTagName("stay");

        foreach (XmlNode syxn in Stay)
        {
            RateCode = syxn.Attributes["rateCode"].Value;
            Quantity = syxn.Attributes["quantity"].Value;
            UnitPrice = Math.Round(Convert.ToDecimal(syxn.Attributes["unitPrice"].Value), 2);
            FromTime = syxn.Attributes["usedfrom"].Value;
            ToTime = syxn.Attributes["usedto"].Value;
            Console.WriteLine("      Staying from " + FromTime + " to " + ToTime);
            Console.WriteLine("      Price Per Day : " + Currency + UnitPrice);
            Console.WriteLine("      Using Rate Code: " + RateCode);
        }
    }
}

我（99.99％）确定它是因为行

XmlNodeList Stay = doc.GetElementsByTagName("stay");

现在，在JQUERY中，我会用“this”替换“doc”（而不是再次获取整个列表，但“this”不起作用（来自VS的“静态属性”消息）。有人可以告诉我我需要做些什么来改变它：

     Room Type: 101
     Room id: abc
  Staying from 9:30 to 10:30
  Price Per Day : 62.5
  Using Rate Code: 1
  Staying from 13:20 to 15:30
  Price Per Day : 60.00
  Using Rate Code: RACK
     Room Type: Brd
     Room id: xyz
   Staying from 9:30 to 10:30
  Price Per Day : 62.5
  Using Rate Code: 1
  Staying from 13:20 to 15:30
  Price Per Day : 60.00
  Using Rate Code: RACK

到这个

     Room Type: 101
     Room id: abc
  Staying from 9:30 to 10:30
  Price Per Day : 62.5
  Using Rate Code: 1
     Room Type: Brd
     Room id: xyz
  Staying from 13:20 to 15:30
  Price Per Day : 60.00
  Using Rate Code: RACK

由于

Answer 1

您要求所有stay元素，而不是当前room中的元素：

XmlNodeList Stay = doc.GetElementsByTagName("stay");

应该是

XmlNodeList Stay = room.GetElementsByTagName("stay");

Answer 2

我想我已经修好了我的替换

XmlNodeList Stay = doc.GetElementByTagName("stay") ;

以下两行

XmlNode oNode = rmxn.SelectSingleNode(".//stays");
XmlNodeList Stay = oNode.SelectNodes("stay");

感谢所有帮助过的人，我希望这可以帮助将来遇到同样问题的人。

c＃foreach循环通过XmlNodeList子节点

2 个答案: