Question

我正在尝试在scala中定义名称+ I，如下所示。

def +I(i1: Int, i2: Int): Int = { .....}

它说＆＃39; =＆＃39;预期但找到了标识符。如果我做I_ +，它可以工作，但为了方便使用，我想要+我。是否不能为定义命名？

Answer 1

可以将这样的名称用于定义，但它看起来不太好。你需要在反引号之间加上名字：

def `+I`(i1: Int, i2: Int): Int = 42

用法：

`+I`(1, 2)

Scala的词法语法在https://www.scala-lang.org/files/archive/spec/2.11/13-syntax-summary.html

中进行了总结

以下是最相关的详细信息：

whiteSpace       ::=  ‘\u0020’ | ‘\u0009’ | ‘\u000D’ | ‘\u000A’
upper            ::=  ‘A’ | … | ‘Z’ | ‘$’ | ‘_’  // and Unicode category Lu
lower            ::=  ‘a’ | … | ‘z’ // and Unicode category Ll
letter           ::=  upper | lower // and Unicode categories Lo, Lt, Nl
digit            ::=  ‘0’ | … | ‘9’
paren            ::=  ‘(’ | ‘)’ | ‘[’ | ‘]’ | ‘{’ | ‘}’
delim            ::=  ‘`’ | ‘'’ | ‘"’ | ‘.’ | ‘;’ | ‘,’
opchar           ::= // printableChar not matched by (whiteSpace | upper | lower |
                     // letter | digit | paren | delim | opchar | Unicode_Sm | Unicode_So)
printableChar    ::= // all characters in [\u0020, \u007F] inclusive
charEscapeSeq    ::= ‘\‘ (‘b‘ | ‘t‘ | ‘n‘ | ‘f‘ | ‘r‘ | ‘"‘ | ‘'‘ | ‘\‘)
op               ::=  opchar {opchar}
varid            ::=  lower idrest
plainid          ::=  upper idrest
                 |  varid
                 |  op
id               ::=  plainid
                 |  ‘`’ stringLiteral ‘`’
idrest           ::=  {letter | digit} [‘_’ op]

FunDcl            ::=  FunSig [‘:’ Type]
FunSig            ::=  id [FunTypeParamClause] ParamClauses

scala定义的命名约定

1 个答案: