有没有办法确保runAction(动画)运行直到完成?

时间:2018-05-04 07:16:22

标签: typescript cocos2d-x

当选定的卡片悬停在它们上方时,我有一张牌向左或向右移动。

一切正常,除非移动太快,多次调用卡片动画而前一个动作没有完成。

我在cocos creator v1.9中使用typescript。

我的脚本看起来像这样。

onMoveCard(): void {

    var i: number = 0;
    // animation to move left or right
    var moveRight: cc.ActionInterval = cc.moveBy(0.1, cc.p(DragCard.currentHandSpacing, 0));
    var moveLeft: cc.ActionInterval = cc.moveBy(0.1, cc.p(-DragCard.currentHandSpacing, 0));

    for (i = 0; i <= Hand.handCards.length - 2; i++) {

        // if card moved one spacing to the left, move the previous card to the right
        if (this.node.x < DragCard.originalX - (DragCard.currentHandSpacing * (i + 1))
            && this.node.x > DragCard.originalX - (DragCard.currentHandSpacing * (i + 2))) {

            if (DragCard.countLeft === i) {
                // prevent conditional statement goes out of array bounds

                if (DragCard.currentHandIndex - (i + 1) >= 0) {
                    Hand.handCards[DragCard.currentHandIndex - (i + 1)].runAction(moveRight.clone()); 
                    // clone so that each animation is run independently
                    DragCard.countLeft++;
                }
            }
        }
        // if the card moved back to the right, move the next card to the left
        if (DragCard.countLeft === (i + 1) && this.node.x > DragCard.originalX - (DragCard.currentHandSpacing * i)) {

            Hand.handCards[DragCard.currentHandIndex - (i + 1)].runAction(moveLeft.clone());
            DragCard.countLeft--;

        }
    }
.
.
.
}

1 个答案:

答案 0 :(得分:0)

我找到了一个解决方案,即在卡片排序之前制作stopAllActions()!