使用R在无NA值(1)a 0之前设置NA

时间:2018-05-03 16:05:09

标签: r date na

我有以下数据框df

time <- c("01/01/1951", "02/01/1951", "03/01/1951", "04/01/1951", "05/01/1951", "06/01/1951", "07/01/1951", "08/01/1951", "09/01/1951", "10/01/1951", "11/01/1951", "12/01/1951", "13/01/1951", "14/01/1951", "15/01/1951", "16/01/1951", "17/01/1951", "18/01/1951", "19/01/1951", "20/01/1951", "21/01/1951", "22/01/1951", "23/01/1951")
member <- c(1,NA,NA,3,NA,NA,NA,NA,NA,1,1,NA,2,NA,NA,NA,NA,NA,1,NA,NA,NA,NA)
df <- data.frame(time, member) 
df$time = as.Date(df$time,format="%d/%m/%Y")

我喜欢&#34;会员&#34;的NA值。在成员为1成为0的一天之前,除了1之前的一天(连续两个),我不希望1成为0,只是在1之前的NA值。

所需的数据框将是:

df
         time member
1  01/01/1951      1
2  02/01/1951     NA
3  03/01/1951     NA
4  04/01/1951      3
5  05/01/1951     NA
6  06/01/1951     NA
7  07/01/1951     NA
8  08/01/1951     NA
9  09/01/1951      0
10 10/01/1951      1
11 11/01/1951      1
12 12/01/1951     NA
13 13/01/1951      2
14 14/01/1951     NA
15 15/01/1951     NA
16 16/01/1951     NA
17 17/01/1951     NA
18 18/01/1951      0
19 19/01/1951      1
20 20/01/1951     NA
21 21/01/1951     NA
22 22/01/1951     NA
23 23/01/1951     NA

想法?

1 个答案:

答案 0 :(得分:0)

因此我们需要检查df$member是否为NA且下一个值为1.当两者都为真时,我们将df$member设为0:

df$member[is.na(df$member) & c(df$member[-1] == 1, FALSE)] = 0
df
#          time member
# 1  1951-01-01      1
# 2  1951-01-02     NA
# 3  1951-01-03     NA
# 4  1951-01-04      3
# 5  1951-01-05     NA
# 6  1951-01-06     NA
# 7  1951-01-07     NA
# 8  1951-01-08     NA
# 9  1951-01-09      0
# 10 1951-01-10      1
# 11 1951-01-11      1
# 12 1951-01-12     NA
# 13 1951-01-13      2
# 14 1951-01-14     NA
# 15 1951-01-15     NA
# 16 1951-01-16     NA
# 17 1951-01-17     NA
# 18 1951-01-18      0
# 19 1951-01-19      1
# 20 1951-01-20     NA
# 21 1951-01-21     NA
# 22 1951-01-22     NA
# 23 1951-01-23     NA