Question

请不要将此标记为已回答的问题，因为我认为这不是关于一般程序，但这是一个我没有意识到的具体事情。所以问题是当我运行该程序时，它应首先删除＆＃34; araba＆＃34;字符串然后插入＆＃34; car＆＃34;字符串在其现有位置。所以我每次都提起dict并打印它但没有任何反应？ THX

tr_mean=["araba","otobus","kus"]
en_mean=["car","bus","dog"]
dictionary={}
for x in tr_mean:
  index=tr_mean.index(x)
  dictionary[x]=en_mean[index]



print tr_mean.index("araba")
for x in tr_mean:
  index=tr_mean.index(x)
  dictionary[x]=en_mean[index]
print words
del tr_mean[tr_mean.index("araba")]
for x in tr_mean:
  index=tr_mean.index(x)
  dictionary[x]=en_mean[index]
print words
tr_mean.insert(0,"car")
for x in tr_mean:
  index=tr_mean.index(x)
  dictionary[x]=en_mean[index]

print words

Answer 1

tr_mean = ["araba", "otobus", "kus"]
en_mean = ["car", "bus", "dog"]
dictionary = {}
for x in tr_mean:
    index = tr_mean.index(x)
    dictionary[x] = en_mean[index]

print tr_mean.index("araba")

在这里，你只是在做同样的事情，不需要。

# for x in tr_mean:
#     index = tr_mean.index(x)
#     dictionary[x] = en_mean[index]

您没有定义words，我猜您打算使用dictionnary？

print dictionary

从"araba"移除tr_mean，tr_mean现在为["otobus", "kus"]

del tr_mean[tr_mean.index("araba")]

之后，我猜你试图“重置”词典

for x in tr_mean:
        index = tr_mean.index(x)
        dictionary[x] = en_mean[index]
    print dictionary

但你所做的只是：

dictionary["otobus"] = "bus"
dictionary["kus"] = "dog",

araba仍然存在于dictionnary !!!

中

在分配新值之前，请使用dictionary.clear()

清除字典

dictionary.clear()
for x in tr_mean:
    index = tr_mean.index(x)
    dictionary[x] = en_mean[index]
print dictionary

或者更好的是，删除最后一段代码，只需从"araba"删除dictionary

del dictionary["araba"]

其他所有事情都保持不变。

tr_mean.insert(0, "car")
for x in tr_mean:
    index = tr_mean.index(x)
    dictionary[x] = en_mean[index]

print dictionary

编辑：如果您想使用“araba”的值将“car”添加为词典的新键，您可以执行以下操作：

dictionary["car"] = dictionary.pop("araba")

.pop()将删除“araba”键并将与“araba”相关联的值提供给新密钥dictionary["car"]

列表元素删除和添加，

1 个答案: