Question

到目前为止，我正在制作刽子手游戏并且进展顺利。我只想声明并打印一系列Missed Letters。 Missed Letters是用户已经输入的字母。

以下是代码：

   public static void chosenWord()  throws IOException{

    String randomWord="";
    Scanner ui = new Scanner (System.in);
    Random rand = new Random();
    randomWord = word.get(rand.nextInt(word.size()));

    String Dashes = new String(new char[randomWord.length()]).replace("\0", "_");
    while(Tries < 6 && Dashes.contains("_")) {
        System.out.print("Guess a Character :");
        System.out.print(randomWord);
        System.out.println(Dashes);
        String guess = ui.next();
        char[] Misses = new char[6];
        String chngeDashes = "";


        for (int i = 0; i < randomWord.length(); i++) {
            if (randomWord.charAt(i) == guess.charAt(0)) {
                chngeDashes += guess.charAt(0);
                System.out.print("Guesses: "+guess.toUpperCase());
            } 
            else if (Dashes.charAt(i) != '_') {
                chngeDashes += randomWord.charAt(i);
            } else {
                chngeDashes += "_";
            }
        }

        if (Dashes.equals(chngeDashes)) {
            Tries++;
            Misses[Tries] = guess.charAt(0);
            System.out.println("Misses: "+Misses[Tries]); //Want to print missed letters
            //gameOver();
        } else {
            Dashes = chngeDashes;
        }
        if (Dashes.equals(randomWord)) {
            System.out.println("Correct! You win! The word was " + randomWord);
        }
    }
}

Answer 1

一个。作为问题的一部分，您应该澄清您的问题，而不是期望人们阅读代码。正确解释您当前的行为，以及您目前正在经历的行为。

B中。我认为你要找的是：＆＃34; Arrays.toString（Misses）＆＃34; （至少当你不恰当地命名时）

在Hangman.java中打印错过的字母数组

1 个答案: