Question

嗨我正在努力弄清楚当我用完猜测或赢得比赛时如何设置一个按钮。我也希望这个按钮能够保留我所留下的胜利，损失和猜测。我目前已经拥有它，因此它将猜测计数到0，但我不认为我还有其他任何东西。我非常乐意帮助你，谢谢你。

from tkinter import *
import random
from time import sleep
import sys

randomNumber = random.randint(1,13)
if randomNumber == 11:
    randomNumber = 'Jack'
elif randomNumber == 12:
    randomNumber = 'Queen'
elif randomNumber == 13:
    randomNumber = 'King'
elif randomNumber == 1:
    randomNumber = 'Ace'
randomSuit = ('Clubs Diamonds Hearts Spades' .split())
cardSuit = random.choice(randomSuit)
card = str(randomNumber) + ' of ' + cardSuit

win = 0
loss = 0
guesses = 5

def submit(s):
    global textentry
    global guesses
    global win
    global loss
    entered_text=textentry.get() #collect text from entry box
    output = Label(window, text='', width=30, height=3, bg='white')
    output.grid(row=8, column=0, sticky=N, pady=20)
    textentry.delete(0, END)

    if card.lower() == entered_text.lower():
        output = Label(window, text='You won!', width=30, height=3, bg='white')
        win = win + 1
        wins = Label(window, text='Wins: ' + str(win), bg='#004d00', fg='white') .grid(row=11, column=0, sticky=W)
        losses = Label(window, text='Losses: ' + str(loss), bg='#004d00', fg='white') .grid(row=12, column=0, sticky=W)
        guessesLeft = Label(window, text='Guesses: ' + str(guesses), bg='#004d00', fg='white') .grid(row=13, column=0, sticky=W)
        output.grid(row=8, column=0, sticky=N, pady=20)
        Button(window, text='Submit', width=6, state=DISABLED, relief=FLAT, disabledforeground='white', bg='red', fg='white') .grid(row=4, column=0, sticky=N)

    elif card.lower() != entered_text.lower():
        guesses = guesses - 1
        wins = Label(window, text='Wins: ' + str(win), bg='#004d00', fg='white') .grid(row=11, column=0, sticky=W)
        losses = Label(window, text='Losses: ' + str(loss), bg='#004d00', fg='white') .grid(row=12, column=0, sticky=W)
        guessesLeft = Label(window, text='Guesses: ' + str(guesses), bg='#004d00', fg='white') .grid(row=13, column=0, sticky=W)
        output = Label(window, text='Wrong, try again.', width=30, height=3, bg='white')
        output.grid(row=8, column=0, sticky=N, pady=20)

    if guesses == 0:
        loss = loss + 1
        output = Label(window, text='', width=30, height=3, bg='white')
        output.grid(row=8, column=0, sticky=N, pady=20)
        output = Label(window, text='''You ran out of guesses, better luck
        next time.The correct card was
        ''' + card, width=30, height=3, bg='white')
        output.grid(row=8, column=0, sticky=N, pady=20)
        Button(window, text='Submit', width=6, state=DISABLED, relief=FLAT, disabledforeground='white', bg='red', fg='white') .grid(row=4, column=0, sticky=N)

return

def stop(e):
    exit()

window = Tk()
window.title('Card Guess!')
window.configure(background='#004D00', cursor='heart')

photo1 = PhotoImage(file='card.gif')
Label (window, image=photo1, bg='black') .grid(row=0, column=0, sticky=W)

Label (window, text='''Welcome to The Card Guesser! You will try and attempt     to guess
the card I am thinking of within 5 guesses! Good luck!''', bg='#004d00', fg='white', font='none 12 bold') .grid(row=1, column=0, sticky=N)

Label (window, text='Guess a card. i.e 8 of Spades:', bg='#004d00', fg='white', font='none 12 bold') .grid(row=2, column=0, sticky=N)

textentry = Entry(window, width=20, bg='white')
textentry.grid(row=3, column=0, sticky=N, pady=20)
textentry.focus_set()

Label (window, text='\nOutput:', bg='#004D00', fg='white', font='font 12 bold') .grid(row=7, column=0, sticky=N) #lable for output

output = Label(window, text='', width=30, height=3, bg='white')
output.grid(row=8, column=0, sticky=N, pady=20)

Label (window, text=card) .grid(row=6, column=0, sticky=W) #get rid of

s = Button(window, text='Submit', width=6, command=submit, relief=FLAT, activebackground='red', bg='green', fg='white')
s.grid(row=4, column=0, sticky=N)
window.bind('<Return>', submit)
s.bind('<Button-1>', submit)
#submit button

e = Button(window, text='Exit', width=6, command=stop, relief=FLAT, activebackground='red', bg='green', fg='white')
e.grid(row=10, column=0, sticky=N) #exit button
window.bind('<Escape>', stop)
e.bind('<Button-1>', stop)

wins = Label(window, text='Wins: ' + str(win), bg='#004d00', fg='white')         .grid(row=11, column=0, sticky=W)
losses = Label(window, text='Losses: ' + str(loss), bg='#004d00', fg='white') .grid(row=12, column=0, sticky=W)
guessesLeft = Label(window, text='Guesses: ' + str(guesses), bg='#004d00', fg='white') .grid(row=13, column=0, sticky=W)


window.mainloop()

Answer 1

我找到了一些东西：

我在调用函数submit()时收到错误：

TypeError: submit() missing 1 required positional argument: 's'

因为我按下按钮时没有传递任何参数。由于你不能将参数用于任何事情，你可以将它写成：

def submit(*s):

星号告诉函数接受零参数并将它们存储在s中。

与stop()功能相同。我也认为破坏窗口可能比使用sys.exit()更好。

def stop(*e):
    window.destroy()

当你给这些buttoans一个回调函数时，你也不需要将它们绑定到鼠标按钮

s.bind('<Button-1>', submit)     # Not necessary

设置按钮

至于按钮，你可以创建它，然后忘记它，直到你想再次显示它：

t = Button(window, text='Try again', ... , command=try_again)
t.grid(row=12, column=0, sticky=N)   # Did not quite understand your layout
t.grid_remove()     # Hide the button

然后在submit()功能中，您可以再次显示它。

if guesses == 0:
    ...
    t.grid()        # It will remember its place

存储获胜，损失和猜测量的最简单方法是您已经拥有的变量。然后编写try_again()函数并让它为变量赋值。

如何设置尝试再次按钮，赢，输和猜测记分牌

1 个答案: