我正在尝试编写一个程序来查找几个句子中的特定单词，但是当我尝试输入单词时出现问题，我已尝试cin.ignore()，cin.sync()和{{ 1}}，一切都行不通。
cin.clear()我不知道#include <iostream>
#include <algorithm>
#include <string>
#include <vector>
using namespace std;
int main()
{
vector<string> svec;
cout << "please input text:(at most 10 lines): " << endl;
while(svec.size() < 10) {
string sentence;
getline(cin, sentence);
transform(sentence.begin(), sentence.end(), sentence.begin(), ::tolower);
svec.push_back(sentence);
if(cin.eof())
break;
}
// I tried to clean up cin here by
// cin.ignore() , cin.sync() and cin.clear()
// none of them work
string wordToFind;
cout << "please input the pattern: ";
cin >> wordToFind; // This line isn't working
// If I print out wordToFind, it contains nothing
transform(wordToFind.begin(), wordToFind.end(), wordToFind.begin(), ::tolower);
bool isFind = false;
int whichLine = 1;
for(vector<string>::iterator iter = svec.begin(); iter != svec.end(); iter++, whichLine++) {
size_t pos = 0;
while((pos = iter->find(wordToFind, pos)) != string::npos) {
cout << "Found at" << endl;
cout << "Line " << whichLine << " column " << pos++ << endl;
isFind = true;
}
}
if(isFind == false)
cout << wordToFind << " not found";
return 0;
}
发生了什么，这是cin缓冲区问题还是其他相关问题？