Question

我正在处理正在处理的项目的cin命令问题。

在下面的代码中，命令要求用户输入1再次尝试或2退出，我有命令cin >> keepGoing;

出于某种原因，这完全被跳过了。我已经尝试清除缓冲区并使用cin.clear();而没有运气。这是代码：

int searchDisplay()
{
    bool flag = false;
    vector<Client> store;
    Client foo;
    int i = 0;
    int totalIt = 0;
    Client search;
    char response;
    int keepGoing;
    string input;

    fstream customer("customer.dat", ios::in);

    if (!customer)
    {
        cout << "Error opening file. Program aborting." << endl;
        return 0;
    }

    i = 0;

    while (!customer.eof())
    {
        store.push_back(foo);

        customer.read(reinterpret_cast<char *>(&store[i]),
                    sizeof (store[i]));

        i = i + 1;
    }
    totalIt = i;

    while (flag == false)
    {
        i = 0;
        cout << store[i].name << endl; //test to see what is in store at i = 0

        cout << "Name:                                " << endl;
        cin  >> search.name;

        while (i < totalIt - 1)
        {
            if (search.name == store[i].name)
            {
                flag = true;
                cout << "Name:             " << store[i].name << endl
                     << "Address 1:        " << store[i].address1 << endl
                     << "Address 2:        " << store[i].address2 << endl
                     << "Phone:            " << store[i].phone << endl
                     << "Account Balance:  " << store[i].acctBal << endl
                     << "Last Payment:     " << store[i].lastPay << endl;
                cout << endl << "Strike any key to continue";
                cin.get(response);
            }
            else
            {
                i = i +1;
                cout << "searched " << i << "times" << endl;
            }
        }

        if (flag == false)
        {
            cout << "There is no record of that name in our files. Hit 1                  
                                      to try again or any number to quit:" << endl;

            cin.clear();
            cin  >> keepGoing;    //HERE IS MY PROBLEM

            if (keepGoing != 1)
            {
                flag = true;
            }
            else
            {
                flag = false;
            }
        }

    }

    customer.close();
    return 1;

}

我发现有类似问题的所有其他问题的答案要么不起作用，要么导致我无法弄清楚的错误。希望我的编码能够帮助您找到更加个性化的答案。谢谢你的帮助。

Answer 1

适合我:(

（对不起，我应该发表评论，但我是新人，我的代表很可怕。）

我尝试使用虚拟Client类和一些#includes（以及一个customer.dat文件并注释掉cout << store[i].name << endl; //test to see what is in store at i = 0）...

它有效。 <击> 100％

如果我没有输入1，那就崩溃了。但如果关键是它正在阅读cin >> keepGoing;就好了。

看起来您的代码很好。希望这在某种程度上有所帮助。

P.S。：我的包括因此：

#include <vector>
#include <fstream>
#include <iostream>

cin里面虽然循环被忽略，需要

1 个答案: