Question

我想要实现的是从@ temp2获取ID列以对应于@ temp1中的intA和intB列我希望看到的最终结果输出看起来像：

intA    intB    'asset1'    'asset2'    'name1' 'name2'

1   1   108 108 Cash    Cash

1   2   108 109 Cash    Commodities

1   3   108 138 Cash    Stock
.
.
.

2   5   109 111 Commodities Equity

以下是我正在使用的一些示例数据：

declare @temp1 table
(
    intA    int,
    intB    int
)
insert @temp1
select 1,1 union all
select 1,2 union all
select 1,3 union all
select 1,4 union all
select 1,5 union all
select 2,1 union all
select 2,2 union all
select 2,3 union all
select 2,4 union all
select 2,5

select * from @temp1
declare @temp2 table
(
    oneup   int,
    id  int,
    name    varchar(30)
)
insert @temp2
select 1,108,'Cash' union all
select 2,109,'Commodities' union all
select 3,138,'Stock' union all
select 4,110,'Bonds' union all
select 5,111,'Equity'

select * from @temp2

select t1.*,t2.* from @temp1 t1
inner join @temp2 t2
on t1.intA = t2.oneup

我无法让联接正常工作，给我一个像我期望的输出。使用SQL2008

感谢您的帮助！

Answer 1

您需要加入@temp2两次，一次为intA，一次为intB。

select t1.intA, t1.intB, 
       t2a.id as asset1,  t2b.id as asset2, 
       t2a.name as name1, t2b.name as name2
    from @temp1 t1
        inner join @temp2 t2a
            on t1.intA = t2a.oneup
        inner join @temp2 t2b
            on t1.intB = t2b.oneup

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