Question

我创建了一个具有以下结构的表 -

$sql = "CREATE TABLE followers
    (
     uid int UNSIGNED NOT NULL UNIQUE,
     PRIMARY KEY(uid),
     follower_count int UNSIGNED ,
     is_my_friend bool,
     status_count int UNSIGNED,
     location varchar(50)
    )";

我需要找到max（status_count + follower_count）且is_my_friend = 1

的人的uid

我编写了以下查询，但我没有得到正确的uid。

SELECT p.uid FROM (select uid,is_my_friend,max(follower_count+status_count) from followers) p WHERE p.is_my_friend = 1;

Answer 1

以下查询将起作用：

Select uid
From followers
Where is_my_friend = 1
Order By (follower_count+status_count) desc LIMIT 0,1

限制0,1适用于MySql。

或者，如果您想要返回仅跟随follower_count + status_count = max的所有行，则这是查询：

Select uid
From followers
Where is_my_friend = 1
  And (follower_count+status_count) = (select max(follower_count+status_count)
                                       from followers
                                       where is_my_friend = 1)

Answer 2

SECLECT uid FROM followers ORDER BY (follower_count + status_count) DESC WHERE is_my_friend = 1

Answer 3

SELECT top 1 uid （FOLLOWER_COUNT + status_count） ascount FROM FROM followers WHERE p.is_my_friend = 1个按totalcount desc排序

如果订单可能，我不是100％。尝试一下，如果没有创建一个组合这些字段的视图

需要有关SQL查询的帮助

3 个答案: