考虑以下数据:
datamichael <- data.frame(x=c(100,200,300,500), y=c(75,100,300,400), row.names = LETTERS[1:4])
dataewan <- data.frame(x=c(200,50,200,600), y=c(100,100,400,300), row.names = LETTERS[1:4])
datatom <- data.frame(x=c(100,150,400,200), y=c(100,100,400,300), row.names = LETTERS[1:4])
datamichaeldataewan <- rbind(datamichael,dataewan)
datamichaeldatatom <- rbind(datamichael,datatom)
dataewandatamichael <- rbind(dataewan, datamichael)
dataewandatatom <- rbind(dataewan, datatom)
datatomdatamichael <- rbind(datatom, datamichael)
datatomdataewan <- rbind(datatom, dataewan)
library(Benchmarking)
effmichaelewan <- dea(datamichaeldataewan$x,datamichaeldataewan$y, XREF=datamichael$x, YREF=datamichael$y)
effmichaeltom <- dea(datamichaeldatatom$x,datamichaeldatatom$y, XREF=datamichael$x, YREF=datamichael$y)
effewanmichael <- dea(dataewandatamichael$x,dataewandatamichael$y, XREF=dataewan$x, YREF=dataewan$y)
effewantom <- dea(dataewandatatom$x,dataewandatatom$y, XREF=dataewan$x, YREF=dataewan$y)
efftommichael <- dea(datatomdatamichael$x,datatomdatamichael$y, XREF=datatom$x, YREF=datatom$y)
efftomewan <- dea(datatomdataewan$x,datatomdataewan$y, XREF=datatom$x, YREF=datatom$y)
我知道我的名字惯例有点令人困惑。现在我想计算迈克尔的加权平均值。那就是:
result1 <- (weighted.mean(eff(effmichaelewan), datamichaeldataewan$y)/
weighted.mean(eff(effewanmichael), dataewandatamichael$y))
result2 <- (weighted.mean(eff(effmichaeltom), datamichaeldatatom$y)/
weighted.mean(eff(efftommichael), datatomdatamichael$y))
是否可以通过循环进行计算?因为我有两个以上的合并数据,汤姆的数据应该用它来划分。
答案 0 :(得分:0)
您可以将输出(dataXXXXXX和effXXXXXXX)放入两个列表中,然后遍历它:
# First order them in the order they appear in your weighted mean calculation
datamichaeldataewan <- rbind(datamichael,dataewan)
dataewandatamichael <- rbind(dataewan, datamichael)
datamichaeldatatom <- rbind(datamichael,datatom)
datatomdatamichael <- rbind(datatom, datamichael)
effmichaelewan <- dea(datamichaeldataewan$x,datamichaeldataewan$y)
effewanmichael <- dea(dataewandatatom$x,dataewandatatom$y)
effmichaeltom <- dea(datamichaeldatatom$x,datamichaeldatatom$y)
efftommichael <- dea(datatomdatamichael$x,datatomdatamichael$y)
# add them to lists
data.list <- list(datamichaeldataewan,dataewandatamichael,datamichaeldatatom,datatomdatamichael)
eff.list <- list(effmichaelewan,effewanmichael,effmichaeltom,efftommichael)
# your loop
for (i in seq(1,3,2)){ # use every other entry as you add plus one to include the following entry in your weighted mean calculation
result1 <- (weighted.mean(eff(eff.list[[i]]), data.list[[i]]$y)/
weighted.mean(eff(eff.list[[i+1]]), data.list[[i+1]]$y))
print(result1)
}
答案 1 :(得分:0)
你可以这样做:
L <- list(datamichael, dataewan, datatom)
library(Benchmarking)
result <- function(x) {
d1 <- rbind(x[[1]], x[[2]])
d2 <- rbind(x[[2]], x[[1]])
eff.d1 <- dea(d1$x, d1$y)
eff.d2 <- dea(d2$x, d2$y)
weighted.mean(eff(eff.d1), d1$y) / weighted.mean(eff(eff.d2), d2$y)
}
combn(L, 2, FUN=result)
要了解您可以做的名字:
n <- c("michael", "ewan", "tom")
combn(n, 2)
datamichael <- data.frame(x=c(100,200,300,500), y=c(75,100,300,400), row.names = LETTERS[1:4])
dataewan <- data.frame(x=c(200,50,200,600), y=c(100,100,400,300), row.names = LETTERS[1:4])
datatom <- data.frame(x=c(100,150,400,200), y=c(100,100,400,300), row.names = LETTERS[1:4])