Question

我想要一个可以检测到手指触摸的应用。如果应用检测到屏幕被点击，我想在那个地方放置一个UIImage。这个应用程序需要有多个用户。到目前为止我有这个：

var users = 0
@IBOutlet weak var Person_1: UIImageView!
@IBOutlet weak var Person_2: UIImageView!
@IBOutlet weak var Person_3: UIImageView!
@IBOutlet weak var Person_4: UIImageView!
@IBOutlet weak var Person_5: UIImageView!
var fingers = [String?](repeating: nil, count:5)

   override func touchesBegan(_ touches: Set<UITouch>, with event: UIEvent?) {
        super.touchesBegan(touches, with: event)
        for touch in touches{
            let point = touch.location(in: self.view)
            for (index,finger)  in fingers.enumerated() {
                if finger == nil {
                    fingers[index] = String(format: "%p", touch)
                    print("finger \(index+1): x= \(point.x) , y= \(point.y)")
                    if index == 0 {
                        Person_1.center = CGPoint(x: point.x , y: point.y)
                        Person_1.isHidden = false
                        users = 1
                    }
                    if index == 1 {
                        Person_2.center = CGPoint(x: point.x , y: point.y)
                        Person_2.isHidden = false
                        users = 2
                    }
                    if index == 2 {
                        Person_3.center = CGPoint(x: point.x , y: point.y)
                        Person_3.isHidden = false
                        users = 3
                    }
                    if index == 3 {
                        Person_4.center = CGPoint(x: point.x , y: point.y)
                        Person_4.isHidden = false
                        users = 4
                    }
                    if index == 4 {
                        Person_5.center = CGPoint(x: point.x , y: point.y)
                        Person_5.isHidden = false
                        users = 5
                    }
                    print("Users: \(users)")
                    break
                }
            }
        }
        check_users()
    }
    func check_users(){
        if users == 5 {
            let timer = Timer.scheduledTimer(timeInterval: 5.0, target: self, selector: #selector(self.choosewinner4), userInfo: nil, repeats: false)
        }
        if users == 4 {
            let timer = Timer.scheduledTimer(timeInterval: 5.0, target: self, selector: #selector(self.choosewinner3), userInfo: nil, repeats: false)
        }
        if users == 3 {
            let timer = Timer.scheduledTimer(timeInterval: 5.0, target: self, selector: #selector(self.choosewinner2), userInfo: nil, repeats: false)
        }
        if users == 2 {
            let timer = Timer.scheduledTimer(timeInterval: 5.0, target: self, selector: #selector(self.choosewinner1), userInfo: nil, repeats: false)
        }
    }

@objc func choosewinner1(){
        let diceRoll1 = Int(arc4random_uniform(2) + 1)
        print(diceRoll1)
        if diceRoll1 == 1 {
            Person_1.isHidden = true
        }
        if diceRoll1 == 2{
            Person_2.isHidden = true
        }
    }

每当新用户触摸屏幕时，用户Int将在用户Int上计算1个用户。我有一个函数可以检查当你有x个用户时需要做什么，称为“check_users（）”。这段代码的问题是，如果你用2个人触摸屏幕，那么用户Int将是2.如果你用3个人触摸屏幕，那么用户Int将是2，然后通过check_users（）函数然后通过check_users（）函数与用户Int = 3.我希望应用程序在通过带有最终用户Int值的users_check（）函数之前等待几秒钟。有谁知道怎么做？

Answer 1

您可以使用方法执行延迟选择器。在延迟使用后调用方法：

perform(#selector(check_users), with: nil, afterDelay: 1)

要取消之前尚未完成的任何请求：

override func touchesBegan(_ touches: Set<UITouch>, with event: UIEvent?) {
    super.touchesBegan(touches, with: event)
    NSObject.cancelPreviousPerformRequests(withTarget: self)
    ...
}

用于touchesBegan功能的计时器

1 个答案: