Question

我不确定如何解决问题。所以我正在编程blackJack，我有我的函数声明（如图所示），对于我的add_card_to_hand函数，我不知道该怎么做。我有两个参数，一个我通过参考传递的手，因为我要改变它的内部值和一张卡;我正在添加到手中的卡片。那么我该如何将卡片添加到手中呢？我也不知道类型，我只是把hand_t，它可能是无效的。

typedef enum { HEARTS, DIAMONDS, SPADES, CLUBS } suit_t;
typedef enum { ACE = 1, TWO, THREE, FOUR, FIVE, SIX, SEVEN, EIGHT,   NINE, TEN, JACK, QUEEN, KING } value_t;

typedef struct {
    suit_t suit;
    value_t value;
} card_t;

typedef struct {
    card_t* deck;
    int num_decks;
    int nextcard;
} shoe_t;

typedef struct {
    card_t playercards[21];
    int num_cards_in_array;
} hand_t;


hand_t add_card_to_hand(hand_t* hand, card_t card) {



  }

Answer 1

#define MAX_HAND_CARDS 21

typedef struct {
    card_t playercards[MAX_HAND_CARDS];
    int num_cards_in_array;
} hand_t;


int add_card_to_hand(hand_t* hand, const card_t card) {

    if (hand->num_cards_in_array >= MAX_HAND_CARDS) {
        return -1;
    }   

    hand->playercards[hand->num_cards_in_array] = card;
    hand->num_cards_in_array++;

    return 0;
}


int main(int argc, char *argv[]) {

    hand_t *hand = calloc(1, sizeof(hand_t));
    card_t *card = malloc(sizeof(card_t));
    card->suit = HEARTS;
    card->value = ACE;

    if (add_card_to_hand(hand, *card)) {
        printf("failed to add Card\n");
    } else {
        printf("card added\n");
    }
    return 0;
}

对黑杰克不太了解，但这应该有用。

黑杰克 - 手上添加一张卡片

1 个答案: