Question

我正在尝试UNION ALL加入两个数据库查询结果。这是我的查询

 SELECT taxrec.* FROM (

    SELECT taxrec.* FROM fa_244.0_trans_tax_details AS taxrec WHERE (taxrec.amount <> 0 OR taxrec.net_amount <> 0) AND !ISNULL(taxrec.reg_type) AND taxrec.tran_date >= '2014-03-03' AND taxrec.tran_date <= '2018-03-31'

 union all 

    SELECT  taxrec.* FROM  fa_244.1_trans_tax_details AS taxrec WHERE (taxrec.amount <> 0 OR taxrec.net_amount <> 0) AND !ISNULL(taxrec.reg_type) AND taxrec.tran_date >= '2014-03-03' AND taxrec.tran_date <= '2018-03-31' 

ORDER BY taxrec.trans_type, taxrec.tran_date, taxrec.trans_no, taxrec.ex_rate ) a

但它显示错误。任何帮助解决问题。＃1250表'taxrec'

回答：

我找到了这个问题的答案。问题是我们不能在主查询中使用Alias，因为它们仅用于子查询。这是问题的解决方案。

SELECT * FROM (

SELECT taxrec.* FROM fa_244.0_trans_tax_details AS taxrec WHERE (taxrec.amount <> 0 OR taxrec.net_amount <> 0) AND !ISNULL(taxrec.reg_type) AND taxrec.tran_date >= '2014-03-03' AND taxrec.tran_date <= '2018-03-31'

union all 

SELECT  taxrec.* FROM  fa_244.1_trans_tax_details AS taxrec WHERE (taxrec.amount <> 0 OR taxrec.net_amount <> 0) AND !ISNULL(taxrec.reg_type) AND taxrec.tran_date >= '2014-03-03' AND taxrec.tran_date <= '2018-03-31' 

ORDER BY trans_type, tran_date, trans_no, ex_rate ) a

就是这样。

Answer 1

已移出问题：

我找到了这个问题的答案。问题是我们不能在主查询中使用别名，因为这些别名仅在子查询中使用。这是解决问题的方法。

const XLSX = require("xlsx");

function readXls(path) {
  let values = [];
  try {
    let wb = null;
    wb = XLSX.readFile(buffer);

    let ws = wb.Sheets[wb.SheetNames[0]];

    let range = XLSX.utils.decode_range(ws["!ref"]).e.r;

    if (range) {
      let rows = XLSX.utils.sheet_to_json(ws, {
        header: "A",
        raw: false,
        range: `A1:ZZ${range+1}`,
        dateNF: "YYYY-MM-DD"
      });

      // here you can compute each row

      return rows
    }
  } catch (error) {
    console.log(error);
  }
}

就是这样。

1250 - 来自其中一个SELECT的表'taxrec'不能用于字段列表

1 个答案: