如何在同一个表中执行多个COUNT(*) SELECTS
...
$query = "SELECT count(*) FROM content_form WHERE read_flag = 0 ";
$query = "SELECT count(*) FROM content_form WHERE read_flag = 1 ";
$query = "SELECT count(*) FROM content_form WHERE read_flag = 0 ";
答案 0 :(得分:2)
$query = "SELECT sum(Case when read_flag=0 then 1 else 0 end) as ReadFlag0Cnt,
sum(Case when read_flag=1 then 1 else 0 end) as ReadFlag1Cnt
FROM content_form";
You can use case statement
答案 1 :(得分:2)
试试这个
SELECT read_flag,count(read_flag) as cnt FROM content_form WHERE read_flag IN (0,1,....) GROUP BY read_flag
答案 2 :(得分:1)
你可以试试这个:
$query = "select (SELECT count(*) FROM content_form WHERE read_flag = 0)
as flag0, (SELECT count(*) FROM content_form WHERE read_flag = 1) as flag1,
(SELECT count(*) FROM content_form WHERE read_flag = 0) as flag0) from content_form";