我无法弄清楚如何阻止消息在客户端的屏幕上出现两次。
运行代码的步骤:
1.在一个终端上运行服务器
2.在两个不同的终端上运行两个客户端
当我运行服务器时 - main方法创建一个Server对象:
public static void main(String[] args) throws IOException {
Server server = new Server();
}
服务器构造函数:
Server() throws IOException {
Date dNow = new Date();
System.out.println("MultiThreadServer started at " + String.format("%tc", dNow));
System.out.println();
ServerSocket server = new ServerSocket(8000);
ClientSockets = new Vector<Socket>();
while (true) {
Socket client = server.accept();
AcceptClient acceptClient = new AcceptClient(client);
System.out.println("Connection from Socket " + "[addr = " + client.getLocalAddress() + ",port = "
+ client.getPort() + ",localport = " + client.getLocalPort() + "] at "
+ String.format("%tc", dNow));
System.out.println();
//System.out.println(clientCount);
}
//server.close();
}
我正在使用Socket连接到服务器。这是我的服务器代码。
的 Server.java
import java.io.IOException;
import java.net.*;
import java.util.Vector;
import java.io.*;
import java.util.*;
import java.io.DataInputStream;
import java.net.ServerSocket;
import java.net.Socket;
import java.time.LocalDateTime;
import java.util.logging.Level;
import java.util.logging.Logger;
import java.text.*;
import java.util.Scanner;
public class Server {
static Vector<Socket> ClientSockets;
int clientCount = 0;
//int i = 0;
Server() throws IOException {
Date dNow = new Date();
System.out.println("MultiThreadServer started at " + String.format("%tc", dNow));
System.out.println();
ServerSocket server = new ServerSocket(8000);
ClientSockets = new Vector<Socket>();
while (true) {
Socket client = server.accept();
AcceptClient acceptClient = new AcceptClient(client);
System.out.println("Connection from Socket " + "[addr = " + client.getLocalAddress() + ",port = "
+ client.getPort() + ",localport = " + client.getLocalPort() + "] at "
+ String.format("%tc", dNow));
System.out.println();
//System.out.println(clientCount);
}
//server.close();
}
public static void main(String[] args) throws IOException {
Server server = new Server();
}
class AcceptClient extends Thread {
Socket ClientSocket;
DataInputStream din;
DataOutputStream dout;
AcceptClient(Socket client) throws IOException {
ClientSocket = client;
din = new DataInputStream(ClientSocket.getInputStream());
dout = new DataOutputStream(ClientSocket.getOutputStream());
//String LoginName = din.readUTF();
//i = clientCount;
clientCount++;
ClientSockets.add(ClientSocket);
//System.out.println(ClientSockets.elementAt(i));
//System.out.println(ClientSockets.elementAt(1));
start();
}
public void run() {
try {
while (true) {
String msgFromClient = din.readUTF();
System.out.println(msgFromClient);
for (int i = 0; i < ClientSockets.size(); i++) {
Socket pSocket = (Socket) ClientSockets.elementAt(i);
DataOutputStream pOut = new DataOutputStream(pSocket.getOutputStream());
pOut.writeUTF(msgFromClient);
pOut.flush();
}
}
} catch (IOException e) {
e.printStackTrace();
}
}
}
}
Client.java
import java.net.Socket;
import java.util.Scanner;
import java.io.*;
import java.net.*;
public class Client implements Runnable{
Socket socketConnection;
DataOutputStream outToServer;
DataInputStream din;
Client() throws UnknownHostException, IOException {
socketConnection = new Socket("127.0.0.1", 8000);
outToServer = new DataOutputStream(socketConnection.getOutputStream());
din = new DataInputStream(socketConnection.getInputStream());
Thread thread;
thread = new Thread(this);
thread.start();
BufferedReader br = null;
String ClientName = null;
Scanner input = new Scanner(System.in);
String SQL = "";
try {
System.out.print("Enter you name: ");
ClientName = input.next();
ClientName += ": ";
//QUERY PASSING
br = new BufferedReader(new InputStreamReader(System.in));
while (!SQL.equalsIgnoreCase("exit")) {
System.out.println();
System.out.print(ClientName);
SQL = br.readLine();
//SQL = input.next();
outToServer.writeUTF(ClientName + SQL);
//outToServer.flush();
//System.out.println(din.readUTF());
}
} catch (Exception e) {
System.out.println(e);
}
}
public static void main(String[] arg) throws UnknownHostException, IOException {
Client client = new Client();
}
public void run() {
while (true) {
try {
System.out.println("\n" + din.readUTF());
} catch (IOException e) {
e.printStackTrace();
}
}
}
}
答案 0 :(得分:1)
之所以这样,是因为您正在向服务器发送客户端在控制台中编写的任何内容,服务器会将其发送回所有客户端(包括发件人) 强>)。
所以你在控制台中写了一条消息(你看到它),然后你就把它作为一个客户端收回了(你又看到了)。
一个简单的解决方法是不将刚收到的消息发送回客户端(他已在控制台中看到它)。将其添加到Server.AcceptClient#run
方法:
for (int i = 0; i < ClientSockets.size(); i++) {
Socket pSocket = (Socket) ClientSockets.elementAt(i);
if(ClientSocket.equals(pSocket)){
continue;
}
...