我是Java编程的新手,正在尝试开发多客户端聊天服务器。
以下是我的代码:
package Server;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.net.DatagramPacket;
import java.net.DatagramSocket;
import java.net.ServerSocket;
import java.net.Socket;
import java.net.SocketException;
import java.util.ArrayList;
import java.util.List;
public class server implements Runnable{
private List<ServerClient> clients = new ArrayList<ServerClient>();
//private String UID;
private int port;
private ServerSocket socket;
private Thread run, manage, send, receive;
private boolean running = false;
public int i=0;
public server(int port){
// this.UID = UID;
this.port = port;
try {
socket = new ServerSocket(port);
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
run = new Thread(this, "Server");
run.start();
}
@Override
public void run() {
// TODO Auto-generated method stub
running = true;
ManageClients();
receive();
}
private void ManageClients(){
manage = new Thread("Manage"){
public void run(){
while(running){
//managing
}
}
};
manage.start();
}
private void receive(){
receive = new Thread("Receive"){
public void run(){
Socket S1 = null;
try {
S1 = socket.accept();
} catch (IOException e1) {
// TODO Auto-generated catch block
e1.printStackTrace();
}
while(running){
/* byte [] data = new byte[1024];
DatagramPacket packet = new DatagramPacket(data, data.length);
try {
socket.receive(packet);
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
String string = new String(packet.getData());
System.out.println(string);*/
/* BufferedReader br = null;
try {
br = new BufferedReader(new InputStreamReader(S1.getInputStream()));
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
try {
String string = br.readLine();
System.out.println(string);
process(string);
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}*/
process(S1);
System.out.println(String.valueOf(i));
i++;
}
}
};
receive.start();
}
private void process(Socket S1){
BufferedReader br = null;
String string = "";
try {
br = new BufferedReader(new InputStreamReader(S1.getInputStream()));
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
try {
string = br.readLine();
System.out.println(string);
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
if(string.startsWith("/c/")){
clients.add(new ServerClient("name", S1.getInetAddress(), S1.getPort(), "UID"));
}
else if(string.startsWith("/ip/")){
//send ip address to raspberry
System.out.println(string);
}
else if(string.startsWith("/r/")){
//send relay command to relay
System.out.println(string);
}
}
}
服务器只接受一个连接。如果我尝试连接其他用户,则控制台不会显示任何输出。
请你指导我出错的地方。
谢谢
答案 0 :(得分:0)
您需要为每个想要连接的客户端多次运行accept
方法...一次。通常人们在while
循环中的单独线程上执行此操作,因为accept
方法正在阻止。
在您的代码中,您似乎只调用accept
一次,因此您只能获得一个客户端连接。
我建议你在这里更改你的代码架构,但是如果你想保持它相同,并且你知道有多少客户端将连接,那么你可以在同步锁中包含对socket的访问,并调用你的{每个客户一次{1}}方法。