SQL选择共享一列的更多行，并在另一列中包含少量值之一

Question

假设我有这样的表：

+-----------------+-----------------+
| name            | playlist        |
+-----------------+-----------------+
| Jay-Z           | chill vibes     |
+-----------------+-----------------+
| Jay-Z           | rap             |
+-----------------+-----------------+
| Jay-Z           | discover weekly |
+-----------------+-----------------+
| Imagine Dragons | discover weekly |
+-----------------+-----------------+
| ZEDD            | discover weekly |
+-----------------+-----------------+
| Imagine Dragons | pop             |
+-----------------+-----------------+

我需要选择播放列表中的作者每周发现和RAP。我所知道的只是播放列表。如何用纯SQL做到这一点，甚至可能吗？

Answer 1

你可以使用过滤器让不同的播放列表的数量等于你正在寻找的数字

  select name  
  from my_table  
  where playlist in ('discover weekly', 'rap')
  group by name
  having count(distinct playlist) = 2

Answer 2

使用分组和计数。见下文：

select name
from table1
where playlist in ('rap','discover weekly')
group by name
having count(distinct playlist) = 2;

Result:  Jay-Z