Question

我的示例表：

CAR OPTIONS

| ID | CAR_ID |    DESCRIPTION |
|----|--------|----------------|
|  1 |      5 | tinted windows |
|  2 |      5 |  power windows |
|  3 |      6 |  power windows |
|  4 |      7 | tinted windows |

如何编写一个sql语句，它接受输入'tinted windows'和'power windows'并返回第1行和第2行（它们在car_id列中共享一个公共值）？

Answer 1

使用WHERE获取与输入匹配的所有行，然后为每个输入获取GROUP BY car_id HAVING至少一行。您可以使用下面的查询来执行此操作。

SELECT car_id 
FROM CarOptions
WHERE (description = "tinted windows" OR 
       description = "power windows")
GROUP BY car_id
HAVING SUM(description = "tinted windows") > 0 AND 
       SUM(description = "power windows") > 0

请参阅demo

要获得整行，

SELECT *
FROM CarOptions
WHERE car_id IN (
  SELECT car_id
  FROM CarOptions
  WHERE (description = "tinted windows" OR
         description = "power windows")
  GROUP BY car_id
  HAVING SUM(description = "tinted windows") > 0 AND
         SUM(description = "power windows") > 0)

Answer 2

在这种特殊情况下，你可以做到

SELECT * 
  FROM caroptions o JOIN
(
  SELECT car_id
    FROM caroptions
   WHERE description IN('tinted windows', 'power windows')
   GROUP BY car_id
  HAVING COUNT(DISTINCT description) = 2
) q  
    ON o.car_id = q.car_id

输出：

| ID | CAR_ID |    DESCRIPTION |
|----|--------|----------------|
|  1 |      5 | tinted windows |
|  2 |      5 |  power windows |

这是 SQLFiddle 演示

选择在一列中共享公共值但由其他值选择的行

2 个答案: