如何在不使用复杂列表功能的情况下返回低于特定阈值的数字列表？

Question

我不知道如何在不使用复杂功能的情况下做到这一点，请帮忙。这是代码的文档字符串：

 '''
 finds all numbers in the list below a certain threshold
    :param numList: a list of numbers
    :threshold: the cutoff (only numbers below this will be included)
    :returns: a new list of all numbers from numList below the threshold
 '''

Answer 1

一种方法

def filterList(numList, threshold):
    return list(filter(lambda x: x < threshold, numList))

另一种方法：

filteredList = [x for x in numList if x < threshold]