Question

我正在尝试获取所有拥有手机号码的联系人。我可以获取联系人。但问题是它给了我重复的联系人。电话号码来了两次。

我使用以下代码来获取联系人。

public static List<RawContact>  getAllContacts(Context context,Account account){
        Log.d(TAG, "*** Looking for local contacts with mobile number!!");
        String phoneNumber = null;
        String email = null;
        int numberOfContacts = 0;
        List<RawContact> newContacts = new ArrayList<RawContact>();
        Uri CONTENT_URI = ContactsContract.Contacts.CONTENT_URI;
        String _ID = ContactsContract.Contacts._ID;
        String DISPLAY_NAME = ContactsContract.Contacts.DISPLAY_NAME;
        String HAS_PHONE_NUMBER = ContactsContract.Contacts.HAS_PHONE_NUMBER;

        Uri PhoneCONTENT_URI = ContactsContract.CommonDataKinds.Phone.CONTENT_URI;
        String Phone_CONTACT_ID = ContactsContract.CommonDataKinds.Phone.CONTACT_ID;
        String NUMBER = ContactsContract.CommonDataKinds.Phone.NUMBER;

        List<RawContact> localNewContacts = new ArrayList<RawContact>();
        final ContentResolver contentResolver = context.getContentResolver();
        final Cursor cursor = contentResolver.query(CONTENT_URI,
                null,
                null,
                null,
                null);

        if(cursor.getCount()>0){
            numberOfContacts = 0;
            Log.d(TAG, "*** Looking for local contacts "+cursor.getCount());
            while(cursor.moveToNext()){
                String contact_id = cursor.getString(cursor.getColumnIndex(_ID));
                String name = cursor.getString(cursor.getColumnIndex(DISPLAY_NAME));
                int hasPhoneNumber = Integer.parseInt(cursor.getString(cursor.getColumnIndex(HAS_PHONE_NUMBER)));
                final long rawContactId = cursor.getLong(DirtyQuery.COLUMN_RAW_CONTACT_ID);
                if (hasPhoneNumber > 0) {
                    //This is to read multiple phone numbers associated with the same contact
                    Cursor phoneCursor = contentResolver.query(PhoneCONTENT_URI, null, ContactsContract.RawContacts.ACCOUNT_TYPE + " <> 'google' "+" AND "+ Phone_CONTACT_ID + " = ?", new String[]{contact_id}, null);
                    while (phoneCursor.moveToNext()) {
                        phoneNumber = phoneCursor.getString(phoneCursor.getColumnIndex(NUMBER));
                        Log.d(TAG,"Phone number is: "+phoneNumber);
                        RawContact rawContact = getRawContact(context, rawContactId);
                        Log.d(TAG, "Contact Name: " + rawContact.getBestName());
                        localNewContacts.add(rawContact);
                    }phoneCursor.close();
            }
            numberOfContacts++;
            Log.d(TAG, "numberOfContacts updated: "+numberOfContacts);
        }

    }
        return localNewContacts;
    }

如何解决此问题

Answer 1

您正在获取重复的联系人，因为您实际上正在阅读RawContacts，而不是联系人。多个RawContact可以并且将包含有关由单个Contact代表的单个人的信息。

您需要在Phones表上进行一次查询，并使用从CONTACT_ID到联系信息的HashMap组织数据，这样您就不会获得重复项。

Contacts DB分为三个主要表：

Contacts - 每个条目代表一个联系人，并将一个或多个RawContacts
RawContacts - 每个条目代表有关某些SyncAdapter（例如Whatsapp，Google，Facebook，Viber）同步的联系人的数据，此组合包含多个数据条目
Data - 有关联系人，电子邮件，电话等的实际数据，每一行都是属于单个RawContact的单个数据

您正试图在Contacts表格上进行查询，并使用Data表格中的字段进行投影，但您无法做到这一点。

您可以使用类似以下代码的内容，只需转换HashMap即可使用ContactModel对象：

Map<Long, List<String>> contacts = new HashMap<Long, List<String>>();

String[] projection = { Data.CONTACT_ID, Data.DISPLAY_NAME, Data.MIMETYPE, Data.DATA1, Data.DATA2, Data.DATA3 };
String selection = Data.MIMETYPE + " IN ('" + Phone.CONTENT_ITEM_TYPE + "')";
Cursor cur = cr.query(Data.CONTENT_URI, projection, selection, null, null);

while (cur != null && cur.moveToNext()) {
    long id = cur.getLong(0);
    String name = cur.getString(1);
    String mime = cur.getString(2); // type of data (e.g. "phone")
    String data = cur.getString(3); // the actual info, e.g. +1-212-555-1234
    int type = cur.getInt(4); // a numeric value representing type: e.g. home / office / personal
    String label = cur.getString(5); // a custom label in case type is "TYPE_CUSTOM"

    String labelStr = Phone.getTypeLabel(getResources(), type, label);
    Log.d(TAG, "got " + id + ", " + name + ", " + kind + " - " + data + " (" + labelStr + ")");

    // add info to existing list if this contact-id was already found, or create a new list in case it's new
    List<String> infos;
    if (contacts.containsKey(id)) {
        infos = contacts.get(id);
    } else {
        infos = new ArrayList<String>();
        infos.add("name = " + name);
        contacts.put(id, infos);
    }
    infos.add(kind + " = " + data + " (" + labelStr + ")");
}

如何从Android联系人内容提供商

1 个答案: