以下是用于获取联系信息的代码:
String id = data.getData().getLastPathSegment();
Cursor cursor = getActivity().getContentResolver()
.query(ContactsContract.Data.CONTENT_URI,
new String[] {ContactsContract.Data.DISPLAY_NAME},
ContactsContract.Data.CONTACT_ID + "=?",
new String[]{id},
null);
// short circuit if we didn't pick a contact
if (cursor.getCount() == 0) {
return;
}
String contact = "";
String contactName = "";
//code to get contact name
if (cursor.moveToFirst() && cursor.getString(0) != null) {
contact = contact + cursor.getString(0) + ",";
contactName = cursor.getString(0);
}
else {
contact = contact + ","; //changed
}
cursor.close();
// code to get phone number
cursor = getActivity().getContentResolver().query(
ContactsContract.CommonDataKinds.Phone.CONTENT_URI,
newString[{ContactsContract.CommonDataKinds.Phone.NUMBER,
ContactsContract.CommonDataKinds.Phone.TYPE},
ContactsContract.CommonDataKinds.Phone.CONTACT_ID + "=?",
new String[]{id},null);
if (cursor.moveToFirst() && cursor.getString(0) != null) {
contact = contact + cursor.getString(0) + ",";
contact = contact + cursor.getString(0) + ",";
}
else {
contact = contact + ",,"; //changed
}
cursor.close();
//Code to get email
cursor = getActivity().getContentResolver()
.query(
ContactsContract.CommonDataKinds.Email.CONTENT_URI,
new String[]{ContactsContract.CommonDataKinds.Email.ADDRESS},
ContactsContract.CommonDataKinds.Email.CONTACT_ID + "=?",
new String[]{id},null);
if (cursor.moveToFirst() && cursor.getString(0) != null) {
contact = contact + cursor.getString(0);
}
cursor.close();
contact = contact.replace("+", "");
Log.i("TAG", "CONTACT INFO = " + contact);
我要做的是:
在这里,我通过内容提供商查询来自通讯录的联系人姓名,电话号码和电子邮件,并将这三者连接成一个字符串,用逗号将它们分隔在字符串中。
问题:
我收到了联系人姓名和电子邮件,没有任何问题。 但是,当我从联系人中选择某些联系人时,返回的电话号码为空。
返回空电话号码的联系人是来自其他国家/地区的电话号码,来自我当前的位置。
我现在在加拿大,当我选择加拿大联系人时,我正确地得到了电话号码。
但是,当我从印度选择电话号码时,不会返回该号码,相反,我会得到空的结果。
当我选择与#34; 12345"等数字联系时,会发生同样的情况。或" 5555555555"等。
我的问题
如果发现电话号码无效,可能是Android正在尝试验证号码的真实性并返回空号码吗? *(可能不是!一定是我的错!)*
我该如何解决这个问题?我无法获得电话号码的值,就像用户在联系人中保存的那样?
我为代码或问题中的任何歧义道歉。我是一名新手程序员,非常感谢您的所有投入!
答案 0 :(得分:2)
我从该代码中观察到的一件事是,您正在使用
阅读联系人ContactsContract.Contacts.CONTENT_URI
我修改了您的代码并创建了一种新方法来打印所有联系人。
public static void fetchContacts(Context context) {
String phoneNumber = null;
Uri CONTENT_URI = ContactsContract.Contacts.CONTENT_URI;
String _ID = ContactsContract.Contacts._ID;
String DISPLAY_NAME = ContactsContract.Contacts.DISPLAY_NAME;
String HAS_PHONE_NUMBER = ContactsContract.Contacts.HAS_PHONE_NUMBER;
Uri PhoneCONTENT_URI = ContactsContract.CommonDataKinds.Phone.CONTENT_URI;
String Phone_CONTACT_ID = ContactsContract.CommonDataKinds.Phone.CONTACT_ID;
String NUMBER = ContactsContract.CommonDataKinds.Phone.NUMBER;
StringBuffer output = new StringBuffer();
ContentResolver contentResolver = context.getContentResolver();
Cursor cursor = contentResolver.query(CONTENT_URI, null,null, null, null);
if (cursor.getCount() > 0) {
while (cursor.moveToNext()) {
String contact_id = cursor.getString(cursor.getColumnIndex( _ID ));
String name = cursor.getString(cursor.getColumnIndex( DISPLAY_NAME ));
long hasPhoneNumber = Long.parseLong(cursor.getString(cursor.getColumnIndex( HAS_PHONE_NUMBER )));
if (hasPhoneNumber > 0) {
output.append("\n Name:" + name);
Cursor phoneCursor = contentResolver.query(PhoneCONTENT_URI, null, Phone_CONTACT_ID + " = ?", new String[] { contact_id }, null);
while (phoneCursor.moveToNext()) {
phoneNumber = phoneCursor.getString(phoneCursor.getColumnIndex(NUMBER));
output.append("\n Number:" + phoneNumber);
System.out.println("Number:::::"+phoneNumber);
System.out.println("Contact:::::"+output.toString());
}
phoneCursor.close();
}
}
}else{
// Toast.makeText(context, "No contacts Found", Toast.LENGTH_LONG).show();
}
}