Question

我在搞清楚一些事情时遇到了一些麻烦。基本上我有2个类，每当我创建对象时，它都可以正常工作。但是当我尝试push_back到main()函数中的向量时，它返回0 0 0（B默认值），如果我尝试创建一个void函数，它会这样做，它给出了分段错误。有什么想法吗？

class Date
{
 public:
   Date(int day=0, int month=0, int year=0) : _day(day), _month(month),_year(year) {}
   int get_day()     { return _day; }
   int get_month()   { return _month; }
   int get_year()    { return _year; }
   void writestuff() { std::cout << _day << "/" << _month << "/" << _year<< std::endl; }
   ~Date(){}
 private:
   int _day;
   int _month;
   int _year;
 };

 class Adatok
 {
 public:
   Adatok(std::string name, std::string path, Date date ): _name(name), _path(path), _date(date) {}
   void writestuff()
   {
      std::cout<<_name<<" "<<_path<<" ";
      _date.writestuff();
      std::cout<<std::endl;
   }
   Adatok(const Adatok& other){}
   Adatok operator= (const Adatok& other){}
   ~Adatok(){}

 private:
   std::string _name;
   std::string _path;
   Date _date;
 };  

 void database(std::string& temp, std::vector<Adatok> my_vec); // this would be the segmentation fault code, it's not implemented anymore

 int main(int argc, char **argv)
 {
   std::vector<Adatok> my_vec;
   std::string temp;
   boost::filesystem::ifstream input_file("input");
    while (getline(input_file, temp))
    {
     //---------------------------------don't mind theese------------------------------------------------------------------
      temp += ',';
      std::string name = temp.substr(temp.find_first_of('"'),temp.find_first_of(','));
      temp.erase(0, name.length() + 1);
      std::string path = temp.substr(temp.find_first_of('"'),temp.find_first_of(','));
      temp.erase(0, path.length() + 1);
      std::string numbers(temp.substr(temp.find_first_of('"') + 1,temp.find_first_of('-')));
      int year, month, day;
      year = std::atoi(numbers.c_str());
      temp.erase(0, temp.find_first_of('-') + 1);
      numbers = temp.substr(0, temp.find_first_of('-'));
      month = std::atoi(numbers.c_str());
      temp.erase(0, temp.find_first_of('-') + 1);
      numbers = temp.substr(0, temp.find_first_of(' '));
      day = std::atoi(numbers.c_str());
      //Date obj(day, month, year);
      //Adatok elem(name, path, obj);
      //---------------------------------------don't mind theese-----------------------------------------------------------------
      my_vec.push_back(Adatok(name,path,Date(day,month,year))); //probably fails
     }
       for(std::vector<Adatok>::iterator it{my_vec.begin()};it !=my_vec.end();it++)
       it -> writestuff();
       return 0;
 }

Answer 1

＆＃34;但是当我尝试将push_back推送到MAIN函数中的向量时，它返回0 0 0（B默认值）＆＃34;

这是因为没有初始化B类的成员变量。这应该在push_back A std::vector对象vecA.push_back(A("name", "path", B(15, 04, 2018)));之后执行此操作：

push_back

如果您对如何使用copy constructor表示怀疑，上面肯定会澄清它。

更新：我已将copy assignment operator和default设置为#include <iostream> #include <string> #include <vector> class Date { public: Date(int day = 0, int month = 0, int year = 0) : _day(day), _month(month),_year(year) {} ~Date(){} int get_day() { return _day; } int get_month() { return _month; } int get_year() { return _year; } void writestuff() { std::cout << _day << "/" << _month << "/" << _year<< std::endl; } private: int _day; int _month; int _year; }; class Adatok { public: Adatok(std::string name, std::string path, Date date ) : _name(name), _path(path), _date(date) {} ~Adatok(){} void writestuff() { std::cout<<_name<<" "<<_path<<" "; _date.writestuff(); std::cout<<std::endl; } //change in copy constructor and copy assignment operator Adatok(const Adatok& other) = default; Adatok& operator= (const Adatok& other) = default; private: std::string _name; std::string _path; Date _date; }; void database(std::string temp, std::vector<Adatok> my_vec) { for(auto& it: my_vec) it.writestuff(); } int main(int argc, char **argv) { std::vector<Adatok> my_vec; int year = 2018, month = 04, day = 15; std::string name = "name1", path = "path1"; my_vec.push_back(Adatok(name,path,Date(day,month,year))); database("something", my_vec); return 0; }并且有效。实时行动：https://www.ideone.com/TlmAm2

db:seed

如何将一个类对象push_back到一个std :: vector中？

1 个答案: