Question

我有以下数据库图。我想根据客户在特定日期范围内创建发票。

我的SQL：

SELECT 
    Treatment.Treatment_Date, 
    Salutation.Value as Title,
    Customer.Firstname,
    Customer.Lastname,
    Address.Value as Street, 
    Postal.Postal, 
    Postal.City, 
    Patient.Name as AnimalName,
    TreatmentType.Type as Treatment,
    Treatment.Price,
    Tax.Value as Tax,
    SUM(Treatment.Price) as TotalExTax,
    SUM(Treatment.Price * Tax.Value / 100) as TotalTax,
    SUM(Treatment.Price) + (SUM(Treatment.Price * Tax.Value / 100)) as TotalPrice

FROM Treatment
INNER JOIN Patient ON Treatment.Patient_FK = Patient.ID
INNER JOIN AnimalType ON Patient.Type_FK = AnimalType.ID
INNER JOIN Customer ON Patient.Owner_FK = Customer.ID
INNER JOIN TreatmentType ON Treatment.TreatmentType_FK = TreatmentType.ID
INNER JOIN Salutation ON Customer.Salutation_FK = Salutation.ID
INNER JOIN Address ON Customer.Address_FK = Address.ID
INNER JOIN Postal ON Address.Postal_FK = Postal.Postal
INNER JOIN Tax ON Treatment.Tax_FK = Tax.ID

WHERE Customer.ID = 151 AND Treatment.Treatment_Date between '11/12/2014 00:00:00 AM' and '12/12/2014 12:00:00 PM'

我的问题在于我的SUM。 TotalExTax，应该计算所有＆＃34;治疗的总价格＆＃34; TotalTax，应该给我总税（25％） TotalPrice，应该给我包含税的价格。

... BUT 它似乎给我随机错误.. 现在它只是说：

Error 8120: Column 'Treatment.Treatment_Date' is invalid in the select list because it is not contained in either an aggregate function or the GROUP BY clause.

我已经搜索了这个问题，据我所知，这是正确的。

Answer 1

当您进行这样的聚合时，您需要有一个GROUP BY，您可以将其放在WHERE子句下面

    guard let dictRes = result as? [String : Any] else {
        print("No data")
        return
    }

    guard let data = dictRes["data"] as? [Any] else {
        return
    }

    for value in data {
        let dictData = value as? [String : Any]
        print("addressDescription : \(dictData!["addressDescription"])")
        print("addressLine1 : \(dictData!["addressLine1"])")
        print("addressLine2 : \(dictData!["addressLine2"])")
        print("addressLine3 : \(dictData!["addressLine3"])")
    }

Answer 2

SELECT 
    Treatment.Treatment_Date, 
    Salutation.Value as Title,
    Customer.Firstname,
    Customer.Lastname,
    Address.Value as Street, 
    Postal.Postal, 
    Postal.City, 
    Patient.Name as AnimalName,
    TreatmentType.Type as Treatment,
    Treatment.Price,
    Tax.Value as Tax,
    SUM(Treatment.Price) as TotalExTax,
    SUM(Treatment.Price * Tax.Value / 100) as TotalTax,
    SUM(Treatment.Price) + (SUM(Treatment.Price * Tax.Value / 100)) as TotalPrice

FROM Treatment
INNER JOIN Patient ON Treatment.Patient_FK = Patient.ID
INNER JOIN AnimalType ON Patient.Type_FK = AnimalType.ID
INNER JOIN Customer ON Patient.Owner_FK = Customer.ID
INNER JOIN TreatmentType ON Treatment.TreatmentType_FK = TreatmentType.ID
INNER JOIN Salutation ON Customer.Salutation_FK = Salutation.ID
INNER JOIN Address ON Customer.Address_FK = Address.ID
INNER JOIN Postal ON Address.Postal_FK = Postal.Postal
INNER JOIN Tax ON Treatment.Tax_FK = Tax.ID

WHERE Customer.ID = 151 AND Treatment.Treatment_Date between '11/12/2014 00:00:00 AM' and '12/12/2014 12:00:00 PM'
group by Treatment.Treatment_Date, 
    Salutation.Value,
    Customer.Firstname,
    Customer.Lastname,
    Address.Value, 
    Postal.Postal, 
    Postal.City, 
    Patient.Name,
    TreatmentType.Type,
    Treatment.Price,
    Tax.Value

Answer 3

SUM是一个与GROUP BY子句配对的聚合。如果您还没有描述哪些列不应该被挤压，则无法对某些列求和。

添加一个GROUP BY子句，其中包含不应聚合的所有列，您可以继续使用。

Answer 4

按

添加分组

/** Exception for poming only applies if no special date is set **/

  if (window.id_product && window.id_product == 49) {
deliveryDate = new Date(
  year,
  month,
  deliveryDay + 5,
  9,
  0,
  0
);

nextDate = new Date(
  year,
  month,
  nextDay,
  9,
  0,
  0);

/** Everything else **/
  }

Answer 5

获取客户ID，其中包含您对临时表所需的值的总和根据需要将临时表与其余表格连接起来。

groupby

来自custTreat的SELECT *

行上的SQL SUM和计算不起作用

5 个答案: