Question

我有一个自动售货机问题，为用户提供3种选择：

水2.可乐3.佳得乐

水= $ 1.00，可乐= $ 1.50，gatorade = $ 2.00

在输入用户的四分之一，硬币，镍币和硬币后，我用美元计算总金额。现在我需要检查总量是否足以满足3种饮料中的每一种。如果金额低于成本，我需要提示用户再试一次，如果金额大，那么我需要为用户的更改金额显示一条消息。我相信这需要while循环和if，elif，else语句。以下是我目前的计划：

create-react-app

现在，我需要检查总金额（用户插入的金额）是大于还是小于他所选饮料的成本。

如果更大，我需要返回更改（显示更改金额的消息）。

如果较小，那么我需要提示用户再次尝试插入硬币。

我该怎么做？

Answer 1

我认为这是你需要做的。还可以根据您的要求采用逻辑并修改代码。

不要复制它。希望它有所帮助。

import sys 
print('You have three drinks to choose from this Vending Machine: \n 1. Water \n 2. Cola \n 3. Gatorade')
water = 1.00
cola = 1.50
gatorade = 2.00
choice = 0
while not choice:
    try:
        choice = int(input('Please select any one of the three choices of drinks (1,2 or 3) from the list above: '))
        if choice not in (1,2,3):
            raise ValueError
    except ValueError:
        choice = 0
        print("That is not a valid choice ! Try again")

if choice == 1:
    print("1. water = $1.00")
    total_to_be = 1.00
elif choice == 2:
    print("2. cola = $1.50")
    total_to_be = 1.50
elif choice == 3:
    print("3. gatorade = $2.00")
    total_to_be = 2.00

qrt = int(input("How many quarters did you insert ?"))
dm = int(input("How many dimes did you insert ?"))
nk = int(input("How many nickels did you insert ?"))
pn = int(input("How many pennies did you insert ?"))

total = qrt/4 + dm/10 + nk/20 + pn/100

# total = round(total, 2)

while total != total_to_be: 

    if total >= total_to_be:
        print(total)
        break

    else:
        print("======================= Please try Again ================================")
        qrt = int(input("How many quarters did you insert ?"))
        dm = int(input("How many dimes did you insert ?"))
        nk = int(input("How many nickels did you insert ?"))
        pn = int(input("How many pennies did you insert ?"))

        total = qrt/4 + dm/10 + nk/20 + pn/100

在python中循环使用if语句？

1 个答案: