我的功能现在看起来像这样:
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答案 0 :(得分:0)
我对您的代码进行了一些更改:
将此添加到您的Manifest中的应用程序级别:
<provider
android:name="android.support.v4.content.FileProvider"
android:authorities="com.example.android.fileprovider"
android:exported="false"
android:grantUriPermissions="true">
<meta-data
android:name="android.support.FILE_PROVIDER_PATHS"
android:resource="@xml/file_paths" />
</provider>
然后创建file_paths.xml
文件:
<paths xmlns:android="http://schemas.android.com/apk/res/android">
<external-cache-path name="my_cache" path="." />
<external-path name="my_images" path="Pictures/" />
</paths>
然后在你的代码中:
private static final String FILE_PROVIDER_AUTHORITY = "com.example.android.fileprovider";
private String mTempPhotoPath;
public void takePhoto() {
// Create the capture image intent
Intent imageCapture= new Intent(MediaStore.ACTION_IMAGE_CAPTURE);
// Ensure that there's a camera activity to handle the intent
if (imageCapture.resolveActivity(getPackageManager()) != null) {
// Create the temporary File where the photo should go
File photoFile = null;
try {
photoFile = createTempImageFile(this);
} catch (IOException ex) {
// Error occurred while creating the File
ex.printStackTrace();
}
// Continue only if the File was successfully created
if (photoFile != null) {
// Get the path of the temporary file
mTempPhotoPath = photoFile.getAbsolutePath();
// Get the content URI for the image file
Uri imageUri = FileProvider.getUriForFile(this,
FILE_PROVIDER_AUTHORITY,
photoFile);
// Add the URI so the camera can store the image
imageCapture.putExtra(MediaStore.EXTRA_OUTPUT, imageUri);
}
static File createTempImageFile(Context context) throws IOException {
String timeStamp = new SimpleDateFormat("yyyyMMdd_HHmmss",
Locale.getDefault()).format(new Date());
String imageFileName = "JPEG_" + timeStamp + "_";
File storageDir = context.getExternalCacheDir();
return File.createTempFile(
imageFileName, /* prefix */
".jpg", /* suffix */
storageDir /* directory */
);
}
//To save image
String mCurrentPhotoPath = null;
private File createImageFile() throws IOException {
// Create an image file name
String timeStamp = new SimpleDateFormat("yyyyMMdd_HHmmss").format(new Date());
String imageFileName = "IMG_" + timeStamp + "_";
File storageDir = new File(Environment.getExternalStoragePublicDirectory(Environment.DIRECTORY_PICTURES) + "/DCIM/Camera");
Log.d(TAG, "createImageFile: Saving image to:" + storageDir);
File image = new File(storageDir, imageFileName);
// Save a file: path for use with ACTION_VIEW intents
mCurrentPhotoPath = image.getAbsolutePath();
//Return the saved image
return mCurrentPhotoPath ;
}
答案 1 :(得分:0)
如果您想在外部存储中保存图像,请使用Externalstoragepublicdirectory功能。
答案 2 :(得分:0)
此意图需要Uri格式的EXTRA_OUTPUT位置,请参阅https://developer.android.com/reference/android/provider/MediaStore.html#ACTION_IMAGE_CAPTURE。某些设备可能理解绝对文件路径,但这不是记录的行为。
您可以使用getExternalMediaDirs()来避免许多权限限制。