Question

我有一个包含两列的表，这些列应该为itemID的组合生成一个唯一的数字，如下所示。

请帮助查询。感谢。

seq_no  ItemId
-------------------
15000   AA-00001152
15000   AA-00001152
15001   AA-00001153
15002   AA-00001154
15002   AA-00001154
15003   AA-00001155
15004   AA-00001156
15004   AA-00001156

编辑：

我的输出应该是这样的uniqueNumber .. 在这里，我的unquenurber应该从15000开始并增加1，但是每个多个相同的Itemid，uniquenumber应该如下所示。

UniqueNumber | seq_no | ItemId      |
+--------------+--------+-------------+
| 15000       | 15000  | AA-00001152 |
+--------------+--------+-------------+
| 15000       | 15000  | AA-00001152 |
+--------------+--------+-------------+
| 15001       | 15001  | AA-00001153 |
+--------------+--------+-------------+
| 15002       | 15002  | AA-00001154 |
+--------------+--------+-------------+
| 15002       | 15002  | AA-00001154 |
+--------------+--------+-------------+
| 15003       | 15003  | AA-00001155 |
+--------------+--------+-------------+
| 15004       | 15004  | AA-00001156 |

Answer 1

如果您想为itemid生成一个重复的唯一编号，可以将ROW_NUMBER()与PARTITION BY ItemId一起使用，如下所示。

这将为每个重复ItemId

生成唯一编号

declare  @table table( seq_no int,   ItemId varchar(100))
insert into @table
values
(15000  , 'AA-00001152'),
(15000  , 'AA-00001152'),
(15001  , 'AA-00001153'),
(15002 ,  'AA-00001154'),
(15002 ,  'AA-00001154'),
(15003 ,  'AA-00001155'),
(15004 ,  'AA-00001156'),
(15004  , 'AA-00001156')

SELECT ROW_NUMBER() OVER (PARTITION BY ItemId ORDER BY ItemId) UniqueNumber,*
FROM @table

<强>输出

+--------------+--------+-------------+
| UniqueNumber | seq_no | ItemId      |
+--------------+--------+-------------+
| 1            | 15000  | AA-00001152 |
+--------------+--------+-------------+
| 2            | 15000  | AA-00001152 |
+--------------+--------+-------------+
| 1            | 15001  | AA-00001153 |
+--------------+--------+-------------+
| 1            | 15002  | AA-00001154 |
+--------------+--------+-------------+
| 2            | 15002  | AA-00001154 |
+--------------+--------+-------------+
| 1            | 15003  | AA-00001155 |
+--------------+--------+-------------+
| 1            | 15004  | AA-00001156 |
+--------------+--------+-------------+
| 2            | 15004  | AA-00001156 |
+--------------+--------+-------------+

如果您想在所有项目中生成唯一编号，您也可以尝试以下操作。

SELECT CAST(CAST(seq_no AS VARCHAR(10)) + CAST(UniqueNumber AS VARCHAR(10)) AS INT) UniqueNumber,seq_no,ItemId
FROM
(
    SELECT  ROW_NUMBER() OVER (PARTITION BY ItemId ORDER BY ItemId) UniqueNumber,*
    FROM @table
) T

<强>输出

+--------------+--------+-------------+
| UniqueNumber | seq_no | ItemId      |
+--------------+--------+-------------+
| 150001       | 15000  | AA-00001152 |
+--------------+--------+-------------+
| 150002       | 15000  | AA-00001152 |
+--------------+--------+-------------+
| 150011       | 15001  | AA-00001153 |
+--------------+--------+-------------+
| 150021       | 15002  | AA-00001154 |
+--------------+--------+-------------+
| 150022       | 15002  | AA-00001154 |
+--------------+--------+-------------+
| 150031       | 15003  | AA-00001155 |
+--------------+--------+-------------+
| 150041       | 15004  | AA-00001156 |
+--------------+--------+-------------+
| 150042       | 15004  | AA-00001156 |
+--------------+--------+-------------+

Answer 2

您似乎想要dense_rank()功能

select *, 
         15000+(DENSE_RANK() over (order by ItemId)-1) UniqueNumber 
from table t

如何为SQL Server中的itemID组合生成唯一编号

2 个答案: