Question

我有这个JSON字符串。我想将它发布到服务器（即使用POST方法）。如何在Android中完成？

JSON字符串：

{
    "clientId": "ID:1234-1234",
    "device": {
        "userAgent": "myUA",
        "capabilities": {
            "sms": true,
            "data": true,
            "gps": true,
            "keyValue": {
                "Key2": "MyValue2",
                "Key1": "myvalue1"
            }
        },
        "screen": {
            "width": 45,
            "height": 32
        },
        "keyValue": {
            "DevcKey2": "myValue2",
            "DevcKey1": "myValue1"
        }
    },
    "time": 1294617435368
}

如何构建此JSON数组并将其POST到服务器？

Answer 1

我自己做了。

JSONObject returnedJObject= new JSONObject();
JSONObject KeyvalspairJObject=new JSONObject ();
JSONObject devcKeyvalspairJObject=new JSONObject ();
JSONObject capabilityJObject=new JSONObject();
JSONObject ScreenDimensionsJObject =new JSONObject();
JSONObject deviceJObject= new JSONObject();
try{
    KeyvalspairJObject.put("key1","val1");
    KeyvalspairJObject.put("key2","val2");
    capabilityJObject.put("sms", false);
    capabilityJObject.put("data", true);
    capabilityJObject.put("gps", true);
    capabilityJObject.put("wifi", true);
    capabilityJObject.put("keyValue", KeyvalspairJObject);
    ScreenDimensionsJObject.put("width", 45);
    ScreenDimensionsJObject.put("height", 45);
    devcKeyvalspairJObject.put("Devckey1","val1");
    devcKeyvalspairJObject.put("DEVCkey2","val2");
    deviceJObject.put("userAgent", "MYUserAgent");
    deviceJObject.put("capabilities", capabilityJObject);
    deviceJObject.put("screen", ScreenDimensionsJObject);
    deviceJObject.put("keyValue", devcKeyvalspairJObject);

    returnedJObject.put("clientId", "ID:1234-1234");
    returnedJObject.put("carrier","TMobile");
    returnedJObject.put("device",deviceJObject);
    returnedJObject.put("time",1294617435);
    returnedJObject.put("msisdn","1234567890");
    returnedJObject.put("timezone","GMT");
}
catch(JSONException e)
{
}

这就是我们如何将JSON数据发送到服务器。

public String putDataToServer(String url,JSONObject returnedJObject) throws Throwable
{
    HttpPost request = new HttpPost(url);
    JSONStringer json = new JSONStringer();
    StringBuilder sb=new StringBuilder();


    if (returnedJObject!=null) 
    {
        Iterator<String> itKeys = returnedJObject.keys();
        if(itKeys.hasNext())
            json.object();
        while (itKeys.hasNext()) 
        {
            String k=itKeys.next();
            json.key(k).value(returnedJObject.get(k));
            Log.e("keys "+k,"value "+returnedJObject.get(k).toString());
        }             
    }
    json.endObject();


    StringEntity entity = new StringEntity(json.toString());
                         entity.setContentType("application/json;charset=UTF-8");
    entity.setContentEncoding(new BasicHeader(HTTP.CONTENT_TYPE,"application/json;charset=UTF-8"));
    request.setHeader("Accept", "application/json");
    request.setEntity(entity); 

    HttpResponse response =null;
    DefaultHttpClient httpClient = new DefaultHttpClient();

    HttpConnectionParams.setSoTimeout(httpClient.getParams(), Constants.ANDROID_CONNECTION_TIMEOUT*1000); 
    HttpConnectionParams.setConnectionTimeout(httpClient.getParams(),Constants.ANDROID_CONNECTION_TIMEOUT*1000); 
    try{
        response = httpClient.execute(request); 
    }
    catch(SocketException se)
    {
        Log.e("SocketException", se+"");
        throw se;
    }
    InputStream in = response.getEntity().getContent();
    BufferedReader reader = new BufferedReader(new InputStreamReader(in));
    String line = null;
    while((line = reader.readLine()) != null){
        sb.append(line);
    }
    return sb.toString();
}

Answer 2

如果你已经将JSON作为String，只需使用常规HTTP连接（URL.openConnection（））进行POST。无需解析它或类似的东西。

Answer 3

看一下这段代码

https://gist.github.com/9457c486af9644cf6b18

参见 retrieveJSONArray（ArrayList jsonArray，String []键）和 retrieveJSONString（ArrayList jsonObject）

Answer 4

JSONObject returnedJObject= new JSONObject();

url = "http://49.50.76.75/website/exxx/api.php";

// makeSignupRequest();

try {
    returnedJObject.put("email",eemail);
    returnedJObject.put("password",passwrd);
    returnedJObject.put("type","customer");
    returnedJObject.put("method","register");
    returnedJObject.put("username",usr);

    try {
        putDataToServer(url, returnedJObject);

    }
    catch (Throwable m) {
        m.printStackTrace();
    }
}

Answer 5

如果这只是一个只有一两个服务调用的“Hobby”应用程序，我会考虑查看异步HTTP或REST库。

有几个值得考虑的因素，包括Google的Volley：https://developer.android.com/training/volley/index.html

来自Square的改造：http://square.github.io/retrofit

Volley是一款优秀的通用异步HTTP库，而Retrofit则专注于实现REST客户端。

这两个库都将处理您在示例中处理的大部分低级细节。

无论您是继续使用DefaultHttpClient代码，还是使用Volley或Retrofit，您肯定会希望确保您的网络请求发生在后台线程上，这样您就不会阻止UI线程。从你的例子中不清楚你是否正在这样做。

Answer 6

您也可以使用Httpurlconnection，请检查链接，然后您就会有更多想法。或Httpsurlconnection

如何将Android中的数据以JSON格式发布到服务器？

6 个答案: