Question

我有以下字符串，

String Action =“CreateUser”; String company =“公司名称”;

但是如何转换上面的字符串与json字符串相同，并将此字符串传递给服务器

{"action":"CreateUser","user":{"company":{"solutionname":"","createdon":"","companyguid":"","nextinvoicenumber":"1000","companystatus":"Active","companyname":"","solutioncode":"InvoiceASAP"},"createdon":"","userstatus":"Active","companyguid":"","addressguid":"","guid":"","firstname":"Renuka","lastname":"Shah","email":"ren40@vprex.com","username":"","password":"renuka","cellphone":"","homephone":"","officephone":"","officeextension":"","faxnumber":"","phoneid":"1","sourceid":"1","primarycontact":"Y","permissioncode":"COMPANYADMIN","address":{"addr1":"","addr2":"","addr3":"","addr4":"","addr5":"","city":"","state":"","postalcode":"","country":"","note":""}}}

任何帮助都将不胜感激。

Answer 1

执行以下操作：http://snipplr.com/view/53225/

String Action="CreateUser"; String company="company name";
try
    {
        JSONObject action=new JSONObject();
        JSONObject user=new JSONObject();
        action.put("action", Action);
        action.put("user", user);

        JSONObject company=new JSONObject();
        user.put("company", company);
        user.put("userstatus", "Active");

        company.put("solutionname", "");
        company.put("nextinvoicenumber", "1000");
        //.... 
    }
    catch (Exception je)
    {

    }

然后将JSONObject（action）传递给服务器..

Answer 2

您将以名称 - 值对的形式将put值放入JSONObject中。

像这样：

public void writeJSON() {
    JSONObject user = new JSONObject();
    JSONObject user2;
    user2 = new JSONObject();
    try {
        user.put("dish_id", "1");
        user.put("dish_custom", "2");
        user.put("quantity", "2");
        user.put("shared", "2");

        user2.put("dish_id", "2");
        user2.put("dish_custom", "2");
        user2.put("quantity", "4");
        user2.put("shared", "3");
    } catch (JSONException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }

如何将此数据转换为JSon格式并将此数据POST到服务器？

2 个答案: