我有一个要求,如果今天是星期一,则运行一个查询,否则运行另一个查询。为此,我写了下面的查询,但我收到以下错误消息。
DECLARE
l_today_date VARCHAR2(15) := TO_CHAR(SYSDATE, 'DAY');
BEGIN
CASE l_today_date
WHEN 'MONDAY' THEN
(SELECT st_time AS SYS_DATE,
start_time AS JOB_START_TIME,
COALESCE (end_job,'Job Is Running') AS JOB_END_TIME,
CASE duration_job
WHEN ' min'
THEN 'Job is Running'
ELSE duration_job
END AS JOB_DURATION,
CASE duration_job
WHEN ' min'
THEN 'Job is Running'
ELSE 'Complete'
END AS job_status
FROM
(SELECT name,
st_time,
ABS(floor(((((st_time - lag(end_time) over (order by end_time desc))*24*60*60)/3600)*3600)/60))
|| ' min' duration_job,
TO_CHAR(st_time, 'hh24:mi:ss') AS start_time,
TO_CHAR(lag(end_time)over(order by end_time desc),'hh24:mi:ss') AS end_job
FROM sc_stask
WHERE name IN ( '111 has started' ,'111 has ended' )
ORDER BY st_time DESC
)
WHERE name = '111 has started');
ELSE
(SELECT st_time AS SYS_DATE,
start_time AS JOB_START_TIME,
COALESCE (end_job,'Job Is Running') AS JOB_END_TIME,
CASE duration_job
WHEN ' min'
THEN 'Job is Running'
ELSE duration_job
END AS JOB_DURATION,
CASE duration_job
WHEN ' min'
THEN 'Job is Running'
ELSE 'Complete'
END AS job_status
FROM
(SELECT name,
st_time,
ABS(floor(((((st_time - lag(end_time)over(order by end_time desc) )*24*60*60)/3600)*3600)/60))
|| ' min' duration_job,
TO_CHAR(st_time, 'hh24:mi:ss') AS start_time,
TO_CHAR(lag(end_time)over(order by end_time desc),'hh24:mi:ss') AS end_job
FROM sc_stask
WHERE name IN ( '111 has started' ,'111 has completed' )
AND TO_CHAR(st_time,'DD/MM/YYYY')=TO_CHAR(SYSDATE,'DD/MM/YYYY')
ORDER BY st_time DESC
)
WHERE name = '111 has started'
);
END CASE;
dbms_output.Put_line(l_today_date);
END;
以下是我遇到的错误消息
Error report -
ORA-06550: line 6, column 6:
PLS-00103: Encountered the symbol "SELECT" when expecting one of the following:
( - + case mod new not null <an identifier>
<a double-quoted delimited-identifier> <a bind variable>
continue avg count current exists max min prior sql stddev
sum variance execute forall merge time timestamp interval
date <a string literal with character set specification>
<a number> <a single-quoted SQL string> pipe
<an alternatively-quoted string literal with character set specification>
<an alternat
ORA-06550: line 22, column 47:
PLS-00103: Encountered the symbol "OVER" when expecting one of the following:
. ( ) , * % & = - + < / > at in is mod remainder not rem =>
<an exponent (**)> <> or != or ~= >= <= <> and or like like2
like4 likec as between || member submultiset
06550. 00000 - "line %s, column %s:\n%s"
*Cause: Usually a PL/SQL compilation error.
有人可以帮我解决这个问题。此外,在每个case语句中运行的查询都可以单独运行。但是当我把它们放回一个时,它们却没有。
答案 0 :(得分:2)
问题在于括号;你不应该在select语句周围有这些:
DECLARE
l_today_date VARCHAR2(15) := TO_CHAR(SYSDATE, 'DAY', 'NLS_DATE_LANGUAGE=ENGLISH');
BEGIN
CASE l_today_date
WHEN 'MONDAY' THEN
SELECT st_time AS SYS_DATE,
...
WHERE name = '111 has started';
ELSE
SELECT st_time AS SYS_DATE,
...
WHERE name = '111 has started';
END CASE;
dbms_output.Put_line(l_today_date);
END;
/
我还在to_char()
添加了可选的第三个参数,因此请确保日期名称是您正在搜索的名称;否则,如果有人从非英语会话中运行它,那么它将无法正常匹配。
顺便提一下,如果您只使用l_tdoay_date
值一次 - 并且最后没有dbms_output
调试调用 - 那么您就不需要该变量;您可以将case
与函数调用一起使用:
BEGIN
CASE TO_CHAR(SYSDATE, 'DAY', 'NLS_DATE_LANGUAGE=ENGLISH')
WHEN 'MONDAY' THEN
...
你可以在这里使用if
代替case
- 或者只使用一个值进行检查,在本例中使用case
可能并没有获得太多收益。
您还可以使用单个查询并将case语句逻辑移动到其where
子句中,例如:
FROM sc_stask
WHERE name IN ( '111 has started' ,'111 has ended' )
AND (TO_CHAR(SYSDATE, 'DAY', 'NLS_DATE_LANGUAGE=ENGLISH') = 'MONDAY'
OR TO_CHAR(st_time,'DD/MM/YYYY')=TO_CHAR(SYSDATE,'DD/MM/YYYY')
)
虽然我通常将最后一部分作为OR TRUNC(st_time) = TRUNC(SYSDATE)
而不是将两者都转换为字符串。无论如何,使用这种方法你可能根本不需要PL / SQL块;如果你确实拥有它,那么@Littlefoot提到你必须选择(或者)查询 INTO 。
答案 1 :(得分:1)
不是CASE
,而是IF
:
begin
if to_char(sysdate, 'DAY') = 'MONDAY' then
select ... query you run on monday;
else
select ... query you run otherwise
end if;
end;
[编辑:为INTO条款添加了示例]
SQL> set serveroutput on
SQL>
SQL> declare
2 l_cnt number;
3 l_today varchar2(10) := to_char(sysdate, 'DAY');
4 begin
5 if l_today = 'THURSDAY' then
6 select count(*)
7 into l_cnt --> this
8 from emp
9 where deptno = 10;
10 else
11 select count(*)
12 into l_cnt
13 from emp
14 where deptno <> 10;
15 end if;
16
17 dbms_output.put_line('Today is ' || l_today || ' and count = ' || l_cnt);
18 end;
19 /
Today is THURSDAY and count = 11
PL/SQL procedure successfully completed.
SQL>