I want to identify all IDs from T1 for which T2 has order category of Veggie/Fruits but were never distributed. Also any IDs that do not have an order of Veggie/Fruits as well. How should I be doing this?
T1: ID 1 2 3 4 5 6 7
T2 T2.ID Category Date Ordered Date Distributed T1.ID 01 Veggie 01-Jan-2018 01-Jan-2018 1 02 Fruits 02-Jan-2018 03-Jan-2018 1 03 Veggie 01-Jan-2018 2 04 Nuts 05-Jan-2018 05-Jan-2018 2 05 Fruits 10-Jan-2018 3 06 Seeds 10-Jan-2018 10-Jan-2018 3 07 Veggie 08-Jan-2018 4 08 Veggie 11-Jan-2018 11-Jan-2018 5 09 Veggie 20-Jan-2018 5 10 Fruit 12-Jan-2018 12-Jan-2018 5 11 Fruit 25-Jan-2018 5 12 Nuts 15-Jan-2018 15-Jan-2018 6 13 Seeds 20-Jan-2018 22-Jan-2018 6 14 Nuts 18-Jan-2018 7
I used a case statement with sum but I am not getting the desired result, the records like T1.2 and T1.3 are being dropped from my result. how should I be correcting my code?
select t1.id,
case when sum (
case when t2.category in ('Veggie','Fruits') and t2.date_distributed is null
then 0
else 1 end)<1
then 1
else 0
end
Desired Output:
2 3 4 6 7
答案 0 :(得分：3)
If I follow the logic correctly, exists comes to mind:
select *
from t1
where exists (select 1
from t2
where t2.id = t1.id and
t2.category in ('Veggie','Fruits') and
t2.date_distributed is null
) or
not exists (select 1
from t2
where t2.id = t1.id and
t2.category in ('Veggie','Fruits')
) ;
EDIT:
I misread the data due to the original formatting of the question. For your question, I'll follow the same approach:
select *
from t1
where not exists (select 1
from t2
where t2.t1_id = t1.id and
t2.category in ('Veggie','Fruits') and
t2.date_distributed is not null
) ;
You seem to want t1.ids where that are not in the specified categories with a distribution date.
答案 1 :(得分：1)
By joining the 2 tables and filtering:
select distinct t1.id from t1 inner join t2
on t2.t1id = t1.id
where
(t2.category in ('Veggie','Fruits') and t2.date_distributed is null)
or
(t2.category not in ('Veggie','Fruits'));
It is not clear in t2 table what the name of the column containing the id from t1 is so I used t2.t1id
答案 2 :(得分：1)
实际上，您想要{strong>不存在的ID 分发的素食或水果。
因此，您使用NOT EXISTS，并且在子查询中，仅考虑具有date_distributed is NOT null的类别中的记录
select *
from t1
where NOT exists (select null
from t2
where t2.t1id = t1.id and
t2.category in ('Veggie','Fruits') and
t2.date_distributed is NOT null
);
ID
----------
2
3
4
6
7
答案 3 :(得分：1)
您可以使用Not Exists两个词来使用multiplication逻辑；
decode(Category,'Veggie',1,'Fruits',1,0)是Zero，即Not Veggie/Fruits 或
nvl2(Date_Distributed,1,0)是Zero（ null ），即Not Distributed
with T2( T2_ID, Category, Date_Distributed, T1_ID ) as
(
select '01','Veggie', date'2018-01-01', 1 from dual union all
select '02','Fruits', date'2018-01-03', 1 from dual union all
select '03','Veggie', null , 2 from dual union all
select '04','Nuts' , date'2018-01-05', 2 from dual union all
select '05','Fruits', null , 3 from dual union all
select '06','Seeds' , date'2018-01-10', 3 from dual union all
select '07','Veggie', null , 4 from dual union all
select '08','Veggie', date'2018-01-11', 5 from dual union all
select '09','Veggie', null , 5 from dual union all
select '10','Fruit' , date'2018-01-12', 5 from dual union all
select '11','Fruit' , null , 5 from dual union all
select '12','Nuts' , date'2018-01-15', 6 from dual union all
select '13','Seeds' , date'2018-01-22', 6 from dual union all
select '14','Nuts' , null , 7 from dual
)
select T1_ID
from T2
group by T1_ID
having sum(decode(Category,'Veggie',1,'Fruits',1,0)*nvl2(Date_Distributed,1,0))=0
order by T1_ID;
T1_ID
-----
2
3
4
6
7
顺便说一句，不需要与T1进行任何联接。如果要使用表T1，则行from T2可以替换为from T1 join T2 on T1.ID = T2.T1_ID。