Question

我从数据库得到以下结果（使用sequelize），结果：

数据库中的JSON：

 [{"codSparePart":"SP001","name":"NAME","description":"DESCRIPTION","codProject":1,"available":1,"codManufacturer":1,"stock":4,"manufacturer.name":"MAN1","manufacturer.description":"DES1","manufacturer.codManufacturer":1}]

在控制器中我执行下一步：

 vm.spareParts = data.data;
            console.log('-------- ' + JSON.stringify(vm.spareParts));
            for (var i = 0; i < vm.spareParts.length; i++) {
                vm.items.push({
                    codSparePart: vm.spareParts[i].codSparePart,
                    name: vm.spareParts[i].name,
                    description: vm.spareParts[i].description,
                    available: vm.spareParts[i].available,
                    codManufacturer: vm.spareParts[i].codManufacturer,
                    nameManufacturer: vm.sparePart[i]['manufacturer.description'],
                    stock: vm.spareParts[i].stock,
                    codProject: vm.spareParts[i].codProject
                });

除了用点读取变量外，所有工作都完美无缺。 nameManufacturer: vm.sparePart[i]['manufacturer.description'] nameManufacturer: vm.sparePart[i]['manufacturer.name']

我如何阅读这些变量，我正在寻找解决方案，但我认为太简单了，而且没有任何相关信息。在此先感谢您的帮助。

Answer 1

您的代码似乎运作正常：

＆＃13;

const array =[{"codSparePart":"SP001","name":"NAME","description":"DESCRIPTION","codProject":1,"available":1,"codManufacturer":1,"stock":4,"manufacturer.name":"MAN1","manufacturer.description":"DES1","manufacturer.codManufacturer":1}]

console.log(array[0]['manufacturer.description']);

＆＃13;

更多信息：How to get JSON objects value if its name contains dots?

Answer 2

您输入错误，将vm.sparePart更改为vm.spareParts

这一行：nameManufacturer: vm.sparePart[i]['manufacturer.description'],

AngularJS：使用带有点的变量读取数组

2 个答案: