Question

我需要帮助才能找到当前代码的最佳实践答案。感谢你的帮助。

如何以最佳方式遍历此数组：

$data = [
    'element1.child.property1'  => 1,
    'element1.child.property2'  => 2,
    'element2.child.name'       => 3,
    'element2.child2.name'      => 4,
    'element2.child2.position'  => 5,
    'element3.child3.position'  => 6,
];

得到这样的答案

$result = [
    'element1' => [
        'child' => [
            'property1' => 1,
            'property2' => 2,
        ]
    ],
    'element2' => [
        'child' => [
            'name' => 3
        ],
        'child2' => [
            'name' => 4,
            'position' => 5
        ]
    ],
    'element3' => [
        'child3' => [
            'position' => 6
        ]
    ],
];

Answer 1

你可以循环遍历数组并用＆＃34;。＆＃34;爆炸每个元素的键，然后填充你的新数组：

<?php

$data = [
    'element1.child.property1'  => 1,
    'element1.child.property2'  => 2,
    'element2.child.name'       => 3,
    'element2.child2.name'      => 4,
    'element2.child2.position'  => 5,
    'element3.child3.position'  => 6,
];

foreach ($data as $key => $value) {
    $key = explode(".", $key);
    $newData[$key[0]][$key[1]][$key[2]] = $value;
}

print_r($newData);
?>

这给了你：

Array
    (
    [element1] => Array
        (
            [child] => Array
                (
                    [property1] => 1
                    [property2] => 2
                )

        )

    [element2] => Array
        (
            [child] => Array
                (
                    [name] => 3
                )

            [child2] => Array
                (
                    [name] => 4
                    [position] => 5
                )

        )

    [element3] => Array
        (
            [child3] => Array
                (
                    [position] => 6
                )

        )

)

Answer 2

这是你的数组：

$data = [
    'element1.child.property1'  => 1,
    'element1.child.property2'  => 2,
    'element2.child.name'       => 3,
    'element2.child2.name'      => 4,
    'element2.child2.position'  => 5,
    'element3.child3.position'  => 6,
];

1 /首先，创建一个结果数组：

$result = array();

2 /然后你将遍历你的数组并构建所需的输出：

foreach ($data as $key => $value) {
    $elt = explode(".", $key);

    // Here you will have :
    // $elt[0] = "elementX";
    // $elt[1] = "child";
    // $elt[2] = "property1"; (OR "name" OR "position"...)


    $result[$elt[0]][$elt[1]][$elt[2]] = $value;
}

3 /现在，如果您查看结果，他看起来就像您想要的输出：

var_dump($result);

$result = [
    'element1' => [
        'child' => [
            'property1' => 1,
            'property2' => 2,
        ]
    ],
    'element2' => [
        'child' => [
            'name' => 3
        ],
        'child2' => [
            'name' => 4,
            'position' => 5
        ]
    ],
    'element3' => [
        'child3' => [
            'position' => 6
        ]
    ],
];

希望有所帮助

Answer 3

对于可变长度和更深或更浅的嵌套更具动态性。您可以使用此函数并使用键作为路径和值来循环您的数组。结果将在$result：

function set($path, &$array=array(), $value=null) {
    $path = explode('.', $path);
    $temp =& $array;

    foreach($path as $key) {
        $temp =& $temp[$key];
    }
    $temp = $value;
}

foreach($data as $path => $value) {
    set($path, $result, $value);
}

有关其他用途，请参阅How to access and manipulate multi-dimensional array by key names / path?。

需要在关联数组中分离键

3 个答案: