Question

我需要在数组中推送更多键及其值。如果我使用下面的代码，第一个密钥对被第二个密钥对替换。

供参考：

使用的代码：

foreach ($projectData['projectsections'] as $key => $name) {
$projectData['projectsections'][$key] = ['name' => $name];
$projectData['projectsections'][$key]= ['id' => '1'];
}

当前结果：

'projectsections' => [
    (int) 0 => [
        'id' => '1'
    ],
    (int) 1 => [
        'id' => '1'
    ]
],

预期：

'projectsections' => [
    (int) 0 => [
        'name' => 'test1',
        'id' => '1'
    ],
    (int) 1 => [
        'name' => 'test2',
        'id' => '1'
    ]
],

如何在PHP中构建此数组？任何一个帮助??

Answer 1

使用

$projectData['projectsections'][$key] = ['name' => $name];
$projectData['projectsections'][$key]= ['id' => '1'];

您正在为$key设置一个新数组。这不是你想要的。

这应该有效：

$projectData['projectsections'][$key] = ['name' => $name, 'id' => '1'];

Answer 2

您需要添加整个数组：

$projectData['projectsections'][$key] = ['name' => $name, 'id' => '1'];

或使用键名添加：

$projectData['projectsections'][$key]['name'] = $name;
$projectData['projectsections'][$key]['id'] = '1';

Answer 3

将其更改为：

foreach ($projectData['projectsections'] as $key => $name) {
  $projectData['projectsections'][$key]['name'] = $name;
  $projectData['projectsections'][$key]['id'] = '1';
}

需要在关联数组中推送键和值吗？

3 个答案: